linux-kernel - Re: [RFC][PATCH] A generic boolean (version 6)

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Date:	Fri, 28 Jul 2006 03:29:55 +0200
From:	ricknu-0@...dent.ltu.se
To:	Nicholas Miell <nmiell@...cast.net>
Cc:	Arnd Bergmann <arnd.bergmann@...ibm.com>,
	linux-kernel@...r.kernel.org, Andrew Morton <akpm@...l.org>,
	Jeff Garzik <jeff@...zik.org>,
	Alexey Dobriyan <adobriyan@...il.com>,
	Vadim Lobanov <vlobanov@...akeasy.net>,
	Jan Engelhardt <jengelh@...ux01.gwdg.de>,
	Shorty Porty <getshorty_@...mail.com>,
	Peter Williams <pwil3058@...pond.net.au>,
	Michael Buesch <mb@...sch.de>,
	Pekka Enberg <penberg@...helsinki.fi>,
	Stefan Richter <stefanr@...6.in-berlin.de>, larsbj@...lik.net,
	Paul Jackson <pj@....com>
Subject: Re: [RFC][PATCH] A generic boolean (version 6)

Citerar Nicholas Miell <nmiell@...cast.net>:

> On Thu, 2006-07-27 at 21:55 +0200, ricknu-0@...dent.ltu.se wrote:
> > Citerar Nicholas Miell <nmiell@...cast.net>:
> > 
> > > If _Bool does end up in the user-kernel ABI, be advised that validating
> > > them will be tricky ("b == true || b == false" or "!!b" won't work), and
> > 
> > Why would !!b not work?
> > I don't think it should end up in the ABI (at least, not yet). Just asking
> > because I'm curious. :)
> > 
> 
> The compiler knows that "b = !!b;" is a no-op.

In what gcc version? Using 4.0.2 myself and got that if b equals 12 (using a
pointer to add the value to the boolean) then !!b equals 1.

/Richard Knutsson
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