linux-kernel - Can I use yield in this way

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Date:	Thu, 26 Jun 2008 20:56:50 +0800
From:	夏亮 <xiaiaxaxi@...u.edu.cn>
To:	linux-kernel@...r.kernel.org
Subject: Can I use yield in this way

Hello,

        I'd like to ask a question about the use of a kernel function,  
yield(); I am working on Intel Core Duo, running Linux 2.6.21 I want  
to let current process be off the cpu when the temperature of cpu is  
too high. I add a function called thermal_balance in the timer  
interrupt. My program is as following,

scheduler_tick()
{
       static int count = 0;
       count++;
       if(count % 100 == 0)
           thermal_balance();
}

static int thermal_balance(void)
{
       int cpu = smp_processor_id();
       struct task_struct* task;
       Get CPU temperature.

       if (temperature is too high){
               task = cpu_rq(cpu)->curr;
               yield();
               Move task to other cpu.
       }
}

       Can yield() be used as above. After I compile the kernel and  
run again. Kernel is not working just as it meets deadlock. And if I  
comment yield(), it runs ok. Could anyone help me?Thanks!

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