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Date:	Tue, 04 Aug 2009 19:33:14 +0200
From:	Peter Zijlstra <peterz@...radead.org>
To:	Martin Schwidefsky <schwidefsky@...ibm.com>
Cc:	Laurent Vivier <Laurent.Vivier@...l.net>,
	Ingo Molnar <mingo@...e.hu>,
	kvm-devel <kvm-devel@...ts.sourceforge.net>,
	linux-kernel <linux-kernel@...r.kernel.org>,
	virtualization <virtualization@...ts.linux-foundation.org>
Subject: Re: [PATCH 0/4] Virtual Machine Time Accounting

On Tue, 2009-08-04 at 19:29 +0200, Martin Schwidefsky wrote:

> > So its going to split user time into user and guest. Does that really
> > make sense? For the host kernel it really is just another user process,
> > no?
> 
> The code (at least in parts) is already upstream. Look at the
> account_guest_time function:
> 
> static void account_guest_time(struct task_struct *p, cputime_t cputime,
>                                cputime_t cputime_scaled)
> {
>         cputime64_t tmp;
>         struct cpu_usage_stat *cpustat = &kstat_this_cpu.cpustat;
> 
>         tmp = cputime_to_cputime64(cputime);
> 
>         /* Add guest time to process. */
>         p->utime = cputime_add(p->utime, cputime);
>         p->utimescaled = cputime_add(p->utimescaled, cputime_scaled);
>         account_group_user_time(p, cputime);
>         p->gtime = cputime_add(p->gtime, cputime);
> 
>         /* Add guest time to cpustat. */
>         cpustat->user = cputime64_add(cpustat->user, tmp);
>         cpustat->guest = cputime64_add(cpustat->guest, tmp);
> }
> 
> The cpu time for a guest is added to p->utime AND p->gtime. That is
> done not to break existing tools that know nothing about guest time.
> A guest time aware tool can subtract the p->gtime from p->utime to
> get the time spent by the process outside of the guest context.

But why? How a vcpu anything other than yet another userspace process?

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