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Date:	Tue, 30 Mar 2010 17:08:32 -0700
From:	"Paul E. McKenney" <paulmck@...ux.vnet.ibm.com>
To:	David Howells <dhowells@...hat.com>
Cc:	Eric Dumazet <eric.dumazet@...il.com>, Trond.Myklebust@...app.com,
	linux-nfs@...r.kernel.org, linux-kernel@...r.kernel.org
Subject: Re: [PATCH] NFS: Fix RCU warnings in
 nfs_inode_return_delegation_noreclaim() [ver #2]

On Wed, Mar 31, 2010 at 12:51:04AM +0100, David Howells wrote:
> Paul E. McKenney <paulmck@...ux.vnet.ibm.com> wrote:
> 
> > Which it is, as long as the lock is held.
> 
> However, in one of the situations I'm thinking of, no lock is held.  All that
> is being tested is whether the pointer to some RCU-protected data is either
> NULL or non-NULL.  For example:
> 
> 	@@ -345,7 +346,7 @@ int nfs_inode_return_delegation(struct inode *inode)
> 		struct nfs_delegation *delegation;
> 		int err = 0;
> 
> 	-	if (rcu_dereference(nfsi->delegation) != NULL) {
> 	+	if (nfsi->delegation != NULL) {
> 			spin_lock(&clp->cl_lock);
> 			delegation = nfs_detach_delegation_locked(nfsi, NULL);
> 			spin_unlock(&clp->cl_lock);
> 
> No lock - RCU or spinlock - is held over the check of nfsi->delegation - which
> causes lockdep to complain about an unguarded rcu_dereference().
> 
> However, the use of rcu_dereference() here is unnecessary with respect to the
> interpolation (where appropriate) of a memory barrier because there is no
> second memory access against which to order.
> 
> That said, the memory access is repeated inside nfs_detach_delegation_locked(),
> which again was wrapped in an rcu_dereference():
> 
> 	 static struct nfs_delegation *nfs_detach_delegation_locked(struct nfs_inode *nfsi, const nfs4_stateid *stateid)
> 	 {
> 	-	struct nfs_delegation *delegation = rcu_dereference(nfsi->delegation);
> 	+	struct nfs_delegation *delegation = nfsi->delegation;
> 
> 		if (delegation == NULL)
> 			goto nomatch;
> 
> which was not necessary for its memory barrier interpolation properties in this
> case because of the spin_lock() the caller now holds.
> 
> 
> Your suggestion of using rcu_dereference_check() in both these places would
> result in two unnecessary memory barriers on something like an Alpha CPU.
> 
> 
> How about:
> 
> 	static struct nfs_delegation *nfs_detach_delegation_locked(struct nfs_inode *nfsi, const nfs4_stateid *stateid)
> 	{
> 		struct nfs_delegation *delegation =
> 			rcu_locked_dereference(nfsi->delegation);
> 		...
> 	}
> 
> where rcu_locked_dereference() only does the lockdep magic and the dereference,
> and does not include a memory barrier.  The documentation of such a function
> would note this may only be used when the pointer is guarded by an exclusive
> lock to prevent it from changing.
> 
> And then:
> 
> 	int nfs_inode_return_delegation(struct inode *inode)
> 	{
> 		struct nfs_client *clp = NFS_SERVER(inode)->nfs_client;
> 		struct nfs_inode *nfsi = NFS_I(inode);
> 		struct nfs_delegation *delegation;
> 		int err = 0;
> 
> 		if (rcu_pointer_not_null(nfsi->delegation)) {
> 			spin_lock(&clp->cl_lock);
> 			delegation = nfs_detach_delegation_locked(nfsi, NULL);
> 			spin_unlock(&clp->cl_lock);
> 			if (delegation != NULL) {
> 				nfs_msync_inode(inode);
> 				err = __nfs_inode_return_delegation(inode, delegation, 1);
> 			}
> 		}
> 		return err;
> 	}
> 
> where rcu_pointer_not_null() simply tests the value of the pointer, casting
> away the sparse RCU annotation and not doing the lockdep check and not
> including a barrier.  It would not return the value of the pointer, thus
> preventing you from needing the barrier as a result.

How about Eric's suggestion of rcu_dereference_protected()?  That name
doesn't imply a lock, which as you say above, isn't always needed to
keep the structure from changing.

							Thanx, Paul
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