linux-kernel - Re: [PATCH 2/8] um: Do not use SUBARCH

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Date:	Thu, 26 Sep 2013 16:24:44 +0200
From:	Richard Weinberger <richard@....at>
To:	Geert Uytterhoeven <geert@...ux-m68k.org>
CC:	Ramkumar Ramachandra <artagnon@...il.com>,
	Linux-Arch <linux-arch@...r.kernel.org>,
	Michal Marek <mmarek@...e.cz>,
	Ralf Baechle <ralf@...ux-mips.org>,
	Paul Mundt <lethal@...ux-sh.org>,
	Jeff Dike <jdike@...toit.com>,
	Guan Xuetao <gxt@...c.pku.edu.cn>,
	Thomas Gleixner <tglx@...utronix.de>,
	Ingo Molnar <mingo@...hat.com>,
	"H. Peter Anvin" <hpa@...or.com>,
	the arch/x86 maintainers <x86@...nel.org>,
	linux-kbuild <linux-kbuild@...r.kernel.org>,
	LKML <linux-kernel@...r.kernel.org>,
	linux-m68k <linux-m68k@...ts.linux-m68k.org>,
	Linux MIPS Mailing List <linux-mips@...ux-mips.org>,
	Linux-sh list <linux-sh@...r.kernel.org>,
	uml-devel <user-mode-linux-devel@...ts.sourceforge.net>
Subject: Re: [PATCH 2/8] um: Do not use SUBARCH

Am 26.09.2013 15:26, schrieb Geert Uytterhoeven:
> On Thu, Sep 26, 2013 at 3:13 PM, Ramkumar Ramachandra
> <artagnon@...il.com> wrote:
>> Ramkumar Ramachandra wrote:
>>> Richard Weinberger wrote:
>>>> I told you already that "make defconfig ARCH=um SUBARCH=x86" will spuriously
>>>> create a x86_64 config on x86_64.
>>>> This breaks existing setups.
>>>
>>> I'll fix this and resubmit soon.
>>
>> Wait a minute. You're now arguing about whether the generic "x86"
>> means i386 or x86_64. Its meaning is already defined in
>> arch/x86/Kconfig and arch/x86/um/Kconfig: see the config 64BIT. Unless
>> i386 is explicitly specified, the default is to build a 64-bit kernel.
>> That is already defined for a normal Linux kernel, and user-mode Linux
>> should not break that convention. So, in the example you pulled out of
>> your hat:
>>
>>   $ make defconfig ARCH=um SUBARCH=x86
>>
>> the user should expect a 64-bit build, and not an i386 build as you
>> say. Both my patches are correct, and the "regression" that you
>> pointed out is a red herring.
> 
> Sorry for chiming in, but... what about cross compiling?
> SUBARCH=x86 should give you a 32-bit ia32 kernel, right?

Correct.
Users expect from SUBARCH=x86 a i386 32bit UML kernel.

Thanks,
//richard

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