linux-kernel - [RFC 1/2] workqueue: use the nearest NUMA node, not the local one

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Date:	Thu, 17 Jul 2014 16:09:58 -0700
From:	Nishanth Aravamudan <nacc@...ux.vnet.ibm.com>
To:	benh@...nel.crashing.org
Cc:	Joonsoo Kim <iamjoonsoo.kim@....com>,
	David Rientjes <rientjes@...gle.com>,
	Wanpeng Li <liwanp@...ux.vnet.ibm.com>,
	Jiang Liu <jiang.liu@...ux.intel.com>,
	Tony Luck <tony.luck@...el.com>,
	Fenghua Yu <fenghua.yu@...el.com>, linux-ia64@...r.kernel.org,
	linux-mm@...ck.org, linuxppc-dev@...ts.ozlabs.org,
	linux-kernel@...r.kernel.org
Subject: [RFC 1/2] workqueue: use the nearest NUMA node, not the local one

In the presence of memoryless nodes, the workqueue code incorrectly uses
cpu_to_node() to determine what node to prefer memory allocations come
from. cpu_to_mem() should be used instead, which will use the nearest
NUMA node with memory.

Signed-off-by: Nishanth Aravamudan <nacc@...ux.vnet.ibm.com>

diff --git a/kernel/workqueue.c b/kernel/workqueue.c
index 35974ac..0bba022 100644
--- a/kernel/workqueue.c
+++ b/kernel/workqueue.c
@@ -3547,7 +3547,12 @@ static struct worker_pool *get_unbound_pool(const struct workqueue_attrs *attrs)
 		for_each_node(node) {
 			if (cpumask_subset(pool->attrs->cpumask,
 					   wq_numa_possible_cpumask[node])) {
-				pool->node = node;
+				/*
+				 * We could use local_memory_node(node) here,
+				 * but it is expensive and the following caches
+				 * the same value.
+				 */
+				pool->node = cpu_to_mem(cpumask_first(pool->attrs->cpumask));
 				break;
 			}
 		}
@@ -4921,7 +4926,7 @@ static int __init init_workqueues(void)
 			pool->cpu = cpu;
 			cpumask_copy(pool->attrs->cpumask, cpumask_of(cpu));
 			pool->attrs->nice = std_nice[i++];
-			pool->node = cpu_to_node(cpu);
+			pool->node = cpu_to_mem(cpu);
 
 			/* alloc pool ID */
 			mutex_lock(&wq_pool_mutex);

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