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Date:	Tue, 29 Jul 2014 18:54:16 +0200
From:	Oleg Nesterov <oleg@...hat.com>
To:	Andy Lutomirski <luto@...capital.net>
Cc:	"linux-kernel@...r.kernel.org" <linux-kernel@...r.kernel.org>,
	Kees Cook <keescook@...omium.org>,
	Will Drewry <wad@...omium.org>, X86 ML <x86@...nel.org>,
	"linux-arm-kernel@...ts.infradead.org" 
	<linux-arm-kernel@...ts.infradead.org>,
	Linux MIPS Mailing List <linux-mips@...ux-mips.org>,
	linux-arch <linux-arch@...r.kernel.org>,
	LSM List <linux-security-module@...r.kernel.org>,
	Alexei Starovoitov <ast@...mgrid.com>,
	"H. Peter Anvin" <hpa@...or.com>
Subject: Re: [PATCH v3 6/8] x86: Split syscall_trace_enter into two phases

On 07/28, Andy Lutomirski wrote:
>
> On Mon, Jul 28, 2014 at 10:37 AM, Oleg Nesterov <oleg@...hat.com> wrote:
> > Hi Andy,
> >
> > I am really sorry for delay.
> >
> > This is on top of the recent change from Kees, right? Could me remind me
> > where can I found the tree this series based on? So that I could actually
> > apply these changes...
>
> https://git.kernel.org/cgit/linux/kernel/git/kees/linux.git/log/?h=seccomp/fastpath
>
> The first four patches are already applied there.

Thanks!

> > If I understand correctly, syscall_trace_enter() can avoid _phase2() above.
> > But we should always call user_exit() unconditionally?
>
> Damnit.  I read that every function called by user_exit, and none of
> them give any indication of why they're needed for traced syscalls but
> not for untraced syscalls.  On a second look, it seems that TIF_NOHZ
> controls it.

Yes, just to trigger the slow path, I guess.

> I'll update the code to call user_exit iff TIF_NOHZ is
> set.

Or perhaps it would be better to not add another user of this (strange) flag
and just call user_exit() unconditionally(). But, yes, you need to use
from "work = flags & (_TIF_WORK_SYSCALL_ENTRY & ~TIF_NOHZ)" then.

> > And we should always set X86_EFLAGS_TF if TIF_SINGLESTEP? IIRC, TF can be
> > actually cleared on a 32bit kernel if we step over sysenter insn?
>
> I don't follow.  If TIF_SINGLESTEP, then phase1 will return a nonzero
> value,

Ah yes, thanks, I missed this.

Oleg.

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