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Date:	Mon, 12 Jan 2015 14:46:59 +0100
From:	Jacek Anaszewski <j.anaszewski@...sung.com>
To:	Pavel Machek <pavel@....cz>
Cc:	linux-leds@...r.kernel.org, linux-media@...r.kernel.org,
	linux-kernel@...r.kernel.org, devicetree@...r.kernel.org,
	kyungmin.park@...sung.com, b.zolnierkie@...sung.com,
	cooloney@...il.com, rpurdie@...ys.net, sakari.ailus@....fi,
	s.nawrocki@...sung.com, Andrzej Hajda <a.hajda@...sung.com>,
	Lee Jones <lee.jones@...aro.org>,
	Chanwoo Choi <cw00.choi@...sung.com>
Subject: Re: [PATCH/RFC v10 08/19] leds: Add support for max77693 mfd flash cell

On 01/12/2015 02:25 PM, Pavel Machek wrote:
> Hi!
>
>>>> +struct max77693_sub_led {
>>>> +	/* related FLED output identifier */
>>>
>>> ->flash LED, about 4x.
>>>
>>>> +/* split composite current @i into two @iout according to @imax weights */
>>>> +static void __max77693_calc_iout(u32 iout[2], u32 i, u32 imax[2])
>>>> +{
>>>> +	u64 t = i;
>>>> +
>>>> +	t *= imax[1];
>>>> +	do_div(t, imax[0] + imax[1]);
>>>> +
>>>> +	iout[1] = (u32)t / FLASH_IOUT_STEP * FLASH_IOUT_STEP;
>>>> +	iout[0] = i - iout[1];
>>>> +}
>>>
>>> Is 64-bit arithmetics neccessary here? Could we do the FLASH_IOUT_STEP
>>> divisons before t *=, so that 64-bit division is not neccessary?
>>
>> It is required. All these operations allow for splitting the composite
>> current into both outputs according to weights given in the imax
>> array.
>
> I know.
>
> What about this?
>
> static void __max77693_calc_iout(u32 iout[2], u32 i, u32 imax[2])
> {
> 	u32 t = i;
>
> 	t *= imax[1] / FLASH_IOUT_STEP;

Let's consider following case:

t = 1000000
imax[1] = 1000000

multiplication of the above will give 10^12 - much more than
it is possible to encode on 32 bits.

> 	t = t / (imax[0] + imax[1]);
> 	t /= FLASH_IOUT_STEP
>
> 	iout[1] = (u32)t;
> 	iout[0] = i - iout[1];
> }
>
> Does it lack precision?
>
> Thanks,
> 									Pavel
>


-- 
Best Regards,
Jacek Anaszewski
--
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