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Date:	Tue, 26 Jan 2016 12:10:10 +0000
From:	Will Deacon <will.deacon@....com>
To:	"Paul E. McKenney" <paulmck@...ux.vnet.ibm.com>
Cc:	Leonid Yegoshin <Leonid.Yegoshin@...tec.com>,
	Peter Zijlstra <peterz@...radead.org>,
	"Michael S. Tsirkin" <mst@...hat.com>,
	linux-kernel@...r.kernel.org, Arnd Bergmann <arnd@...db.de>,
	linux-arch@...r.kernel.org,
	Andrew Cooper <andrew.cooper3@...rix.com>,
	Russell King - ARM Linux <linux@....linux.org.uk>,
	virtualization@...ts.linux-foundation.org,
	Stefano Stabellini <stefano.stabellini@...citrix.com>,
	Thomas Gleixner <tglx@...utronix.de>,
	Ingo Molnar <mingo@...e.hu>, "H. Peter Anvin" <hpa@...or.com>,
	Joe Perches <joe@...ches.com>,
	David Miller <davem@...emloft.net>, linux-ia64@...r.kernel.org,
	linuxppc-dev@...ts.ozlabs.org, linux-s390@...r.kernel.org,
	sparclinux@...r.kernel.org, linux-arm-kernel@...ts.infradead.org,
	linux-metag@...r.kernel.org, linux-mips@...ux-mips.org,
	x86@...nel.org, user-mode-linux-devel@...ts.sourceforge.net,
	adi-buildroot-devel@...ts.sourceforge.net,
	linux-sh@...r.kernel.org, linux-xtensa@...ux-xtensa.org,
	xen-devel@...ts.xenproject.org, Ralf Baechle <ralf@...ux-mips.org>,
	Ingo Molnar <mingo@...nel.org>, ddaney.cavm@...il.com,
	james.hogan@...tec.com, Michael Ellerman <mpe@...erman.id.au>
Subject: Re: [v3,11/41] mips: reuse asm-generic/barrier.h

On Mon, Jan 25, 2016 at 05:06:46PM -0800, Paul E. McKenney wrote:
> On Mon, Jan 25, 2016 at 02:41:34PM +0000, Will Deacon wrote:
> > On Fri, Jan 15, 2016 at 11:28:45AM -0800, Paul E. McKenney wrote:
> > > On Fri, Jan 15, 2016 at 09:54:01AM -0800, Paul E. McKenney wrote:
> > > > On Fri, Jan 15, 2016 at 10:24:32AM +0000, Will Deacon wrote:
> > > > > See my earlier reply [1] (but also, your WRC Linux example looks more
> > > > > like a variant on WWC and I couldn't really follow it).
> > > > 
> > > > I will revisit my WRC Linux example.  And yes, creating litmus tests
> > > > that use non-fake dependencies is still a bit of an undertaking.  :-/
> > > > I am sure that it will seem more natural with time and experience...
> > > 
> > > Hmmm...  You are quite right, I did do WWC.  I need to change cpu2()'s
> > > last access from a store to a load to get WRC.  Plus the levels of
> > > indirection definitely didn't match up, did they?
> > 
> > Nope, it was pretty baffling!
> 
> "It is a service that I provide."  ;-)
> 
> > > 	struct foo {
> > > 		struct foo *next;
> > > 	};
> > > 	struct foo a;
> > > 	struct foo b;
> > > 	struct foo c = { &a };
> > > 	struct foo d = { &b };
> > > 	struct foo x = { &c };
> > > 	struct foo y = { &d };
> > > 	struct foo *r1, *r2, *r3;
> > > 
> > > 	void cpu0(void)
> > > 	{
> > > 		WRITE_ONCE(x.next, &y);
> > > 	}
> > > 
> > > 	void cpu1(void)
> > > 	{
> > > 		r1 = lockless_dereference(x.next);
> > > 		WRITE_ONCE(r1->next, &x);
> > > 	}
> > > 
> > > 	void cpu2(void)
> > > 	{
> > > 		r2 = lockless_dereference(y.next);
> > > 		r3 = READ_ONCE(r2->next);
> > > 	}
> > > 
> > > In this case, it is legal to end the run with:
> > > 
> > > 	r1 == &y && r2 == &x && r3 == &c
> > > 
> > > Please see below for a ppcmem litmus test.
> > > 
> > > So, did I get it right this time?  ;-)
> > 
> > The code above looks correct to me (in that it matches WRC+addrs),
> > but your litmus test:
> > 
> > > PPC WRCnf+addrs
> > > ""
> > > {
> > > 0:r2=x; 0:r3=y;
> > > 1:r2=x; 1:r3=y;
> > > 2:r2=x; 2:r3=y;
> > > c=a; d=b; x=c; y=d;
> > > }
> > >  P0           | P1            | P2            ;
> > >  stw r3,0(r2) | lwz r8,0(r2)  | lwz r8,0(r3)  ;
> > >               | stw r2,0(r3)  | lwz r9,0(r8)  ;
> > > exists
> > > (1:r8=y /\ 2:r8=x /\ 2:r9=c)
> > 
> > Seems to be missing the address dependency on P1.
> 
> You are quite correct!  How about the following?

I think that's it!

> As before, both herd and ppcmem say that the cycle is allowed, as
> expected, given non-transitive ordering.  To prohibit the cycle, P1
> needs a suitable memory-barrier instruction.
> 
> ------------------------------------------------------------------------
> 
> PPC WRCnf+addrs
> ""
> {
> 0:r2=x; 0:r3=y;
> 1:r2=x; 1:r3=y;
> 2:r2=x; 2:r3=y;
> c=a; d=b; x=c; y=d;
> }
>  P0           | P1            | P2            ;
>  stw r3,0(r2) | lwz r8,0(r2)  | lwz r8,0(r3)  ;
>               | stw r2,0(r8)  | lwz r9,0(r8)  ;
> exists
> (1:r8=y /\ 2:r8=x /\ 2:r9=c)

Agreed.

Will

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