linux-kernel - [patch] mfd: 88pm80x: Double shifting bug in suspend/resume

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Date:	Thu, 4 Aug 2016 08:26:56 +0300
From:	Dan Carpenter <dan.carpenter@...cle.com>
To:	Lee Jones <lee.jones@...aro.org>, Qiao Zhou <zhouqiao@...vell.com>
Cc:	linux-kernel@...r.kernel.org, kernel-janitors@...r.kernel.org
Subject: [patch] mfd: 88pm80x: Double shifting bug in suspend/resume

set_bit() and clear_bit() take the bit number so this code is really
doing "1 << (1 << irq)" which is a double shift bug.  It's done
consistently so it won't cause a problem unless "irq" is more than 4.

Fixes: 70c6cce04066 ('mfd: Support 88pm80x in 80x driver')
Signed-off-by: Dan Carpenter <dan.carpenter@...cle.com>

diff --git a/include/linux/mfd/88pm80x.h b/include/linux/mfd/88pm80x.h
index d409ceb..c118a7e 100644
--- a/include/linux/mfd/88pm80x.h
+++ b/include/linux/mfd/88pm80x.h
@@ -350,7 +350,7 @@ static inline int pm80x_dev_suspend(struct device *dev)
 	int irq = platform_get_irq(pdev, 0);
 
 	if (device_may_wakeup(dev))
-		set_bit((1 << irq), &chip->wu_flag);
+		set_bit(irq, &chip->wu_flag);
 
 	return 0;
 }
@@ -362,7 +362,7 @@ static inline int pm80x_dev_resume(struct device *dev)
 	int irq = platform_get_irq(pdev, 0);
 
 	if (device_may_wakeup(dev))
-		clear_bit((1 << irq), &chip->wu_flag);
+		clear_bit(irq, &chip->wu_flag);
 
 	return 0;
 }