linux-kernel - Re: [RFC v1 08/14] bus1: implement peer management context

lists.openwall.net		lists / announce owl-users owl-dev john-users john-dev passwdqc-users yescrypt popa3d-users / oss-security kernel-hardening musl sabotage tlsify passwords / crypt-dev xvendor / Bugtraq Full-Disclosure linux-kernel linux-netdev linux-ext4 linux-hardening linux-cve-announce PHC
Open Source and information security mailing list archives

Hash Suite: Windows password security audit tool. GUI, reports in PDF.

[<prev] [next>] [<thread-prev] [thread-next>] [day] [month] [year] [list]

Date:   Fri, 28 Oct 2016 14:06:56 +0200
From:   Richard Weinberger <richard.weinberger@...il.com>
To:     David Herrmann <dh.herrmann@...il.com>
Cc:     LKML <linux-kernel@...r.kernel.org>,
        Andy Lutomirski <luto@...capital.net>,
        Jiri Kosina <jikos@...nel.org>, Greg KH <greg@...ah.com>,
        Hannes Reinecke <hare@...e.com>,
        Steven Rostedt <rostedt@...dmis.org>,
        Arnd Bergmann <arnd@...db.de>, Tom Gundersen <teg@...m.no>,
        Josh Triplett <josh@...htriplett.org>,
        Linus Torvalds <torvalds@...ux-foundation.org>,
        Andrew Morton <akpm@...ux-foundation.org>
Subject: Re: [RFC v1 08/14] bus1: implement peer management context

David, Tom,

On Wed, Oct 26, 2016 at 9:18 PM, David Herrmann <dh.herrmann@...il.com> wrote:
> +struct bus1_peer *bus1_peer_new(void)
> +{
> +       static atomic64_t peer_ids = ATOMIC64_INIT(0);
> +       const struct cred *cred = current_cred();
> +       struct bus1_peer *peer;
> +       struct bus1_user *user;
> +
> +       user = bus1_user_ref_by_uid(cred->uid);
> +       if (IS_ERR(user))
> +               return ERR_CAST(user);
> +
> +       peer = kmalloc(sizeof(*peer), GFP_KERNEL);
> +       if (!peer) {
> +               bus1_user_unref(user);
> +               return ERR_PTR(-ENOMEM);
> +       }
> +
> +       /* initialize constant fields */
> +       peer->id = atomic64_inc_return(&peer_ids);

What is the purpose of this id? Do other components depend on it
and are they aware of possible overflows?
Since it is an 64bit integer overflowing it is hard but not impossible.

-- 
Thanks,
//richard