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Date:	Thu, 28 Jul 2011 15:06:52 +0800
From:	hubert Liao <liao.hubertt@...il.com>
To:	"John W. Linville" <linville@...driver.com>
Cc:	wlanfae@...ltek.com, Larry Finger <Larry.Finger@...inger.net>,
	Chaoming Li <chaoming_li@...lsil.com.cn>,
	linux-wireless@...r.kernel.org, netdev@...r.kernel.org,
	linux-kernel@...r.kernel.org
Subject: Re: Oops when insmod rtl8192ce

2011/7/27 John W. Linville <linville@...driver.com>:
> On Wed, Jul 27, 2011 at 05:20:15PM +0800, hubert Liao wrote:
>> Hi,
>>
>> We got an oops when insmod rtl8192ce module (the board is an ARM soc),
>> accroding the oops message, find it's because in rtl_pci_probe() called
>> _rtl_pci_find_adapter(),
>> in this funcation, the  pdev->bus->self is a NULL pointer .
>>
>> static boot _rtl_pci_find_adapter(strcut pci_dev *dev,
>>               struct ieee80211_hw *hw)
>> {
>>
>> struct pci_dev *bridge_pdev = pdev->bus->self;   //line 1601
>> ...
>>
>> pcipriv->ndis_adapter.pcibridge_vendorid = bridge_pdev->vendor; <-- [oops
>> here] line 1700
>>
>> ...
>> }
>>
>> here, I just want to know why the bus->self  is NULL?
>
> pdev is coming straight from what is passed to the PCI probe routine.
> It seems like pdev->bus->self should already be set before that
> happens.
>
Yes, I think it should be initialized when added the pci bus bridge,
I have checked the mach-kirkwood(my board is arch/arm/mach-kirkwood)
pcie related code, and I think when system initialized should call
kirkwood_pcie_init() ->
            kirkwood_pcie_scan_bus() ->
                           pci_scan_bus() ->
                                    pci_bus_add_devices()
if the pci_bus->self  was initialized in pci_bus_add_devices()?
Maybe the code is too complex for me ,  I really can not find where
set the “->self" member?

> Please open a bug at bugzilla.kernel.org to help us keep track of
> this -- thanks!
>
I have committed it the url,
https://bugzilla.kernel.org/show_bug.cgi?id=40212
> John
> --
> John W. Linville                Someday the world will need a hero, and you
> linville@...driver.com                  might be all we have.  Be ready.
>
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