netdev - Single socket with TX_RING and RX

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Date:	Wed, 15 May 2013 12:53:55 +0000 (UTC)
From:	Ricardo Tubío <rtpardavila@...il.com>
To:	netdev@...r.kernel.org
Subject: Single socket with TX_RING and RX_RING

Once I tell kernel to export the TX_RING through setsockopt() (see code
below) I always get an error (EBUSY) if i try to tell kernel to export the
RX_RING with the same socket descriptor. Therefore, I have to open an
additional socket for the RX_RING and I require of two sockets when I though
that I would only require of one socket for both TX and RX using mmap()ed
memory.

Do I need both sockets or am I doing something wrong?

Code: 

/* init_ring; type = {PACKET_TX_RING, PACKET_RX_RING} */
void *init_ring(const int socket_fd, const int type)
{
  	
	void *ring = NULL;

	int ring_access_flags = PROT_READ | PROT_WRITE;
	tpacket_req_t *p = init_tpacket_req(FRAMES_PER_RING);
	int ring_len = ( p->tp_block_size ) * ( p->tp_block_nr );
  	
  	if ( setsockopt(socket_fd, SOL_PACKET, type,
                          p, LEN__TPACKET_REQ) < 0 )
	{
		log_sys_error("Setting socket options for this ring");
	}

	// 2) open ring
  	if ( ( ring = mmap(NULL, ring_len, ring_access_flags, MAP_SHARED,
  						socket_fd, 0) ) == NULL )
	{
		log_sys_error("mmap()ing error");
	}
	
	return(ring);
	
}


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