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Date: Wed, 19 Jul 2023 09:27:43 +0200
From: Hannes Reinecke <hare@...e.de>
To: Jakub Kicinski <kuba@...nel.org>
Cc: Sagi Grimberg <sagi@...mberg.me>,
 "linux-nvme@...ts.infradead.org" <linux-nvme@...ts.infradead.org>,
 "open list:NETWORKING [GENERAL]" <netdev@...r.kernel.org>
Subject: Re: nvme-tls and TCP window full

On 7/18/23 20:59, Jakub Kicinski wrote:
> On Thu, 13 Jul 2023 12:16:13 +0200 Hannes Reinecke wrote:
>>>> And my reading seems that the current in-kernel TLS implementation
>>>> assumes TCP as the underlying transport anyway, so no harm done.
>>>> Jakub?
>>>
>>> While it is correct that the assumption for tcp only, I think the
>>> right thing to do would be to store the original read_sock and call
>>> that...
>>
>> Ah, sure. Or that.
> 
> Yup, sorry for late reply, read_sock could also be replaced by BPF
> or some other thing, even if it's always TCP "at the bottom".

Hmm. So what do you suggest?
Remember, the current patch does this:

@@ -377,7 +376,7 @@ static int tls_strp_read_copyin(struct tls_strparser 
*strp)
         desc.count = 1; /* give more than one skb per call */

         /* sk should be locked here, so okay to do read_sock */
-       sock->ops->read_sock(strp->sk, &desc, tls_strp_copyin);
+       tcp_read_sock(strp->sk, &desc, tls_strp_copyin);

         return desc.error;
  }

precisely because ->read_sock() gets redirected when TLS engages.
And also remember TLS does _not_ use the normal redirection by 
intercepting the callbacks from 'struct sock', but rather replaces the 
->ops callback in struct socket.

So I'm slightly at a loss on how to implement a new callback without 
having to redo the entire TLS handover.
Hence I vastly prefer just the simple patch by using tcp_read_sock() 
directly.

Cheers,

Hannes
-- 
Dr. Hannes Reinecke                Kernel Storage Architect
hare@...e.de                              +49 911 74053 688
SUSE Software Solutions GmbH, Maxfeldstr. 5, 90409 Nürnberg
HRB 36809 (AG Nürnberg), Geschäftsführer: Ivo Totev, Andrew
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