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Date:	Mon, 02 May 2011 15:30:23 +0300
From:	Surbhi Palande <surbhi.palande@...ntu.com>
To:	Jan Kara <jack@...e.cz>
CC:	Dave Chinner <david@...morbit.com>,
	Toshiyuki Okajima <toshi.okajima@...fujitsu.com>,
	Ted Ts'o <tytso@....edu>,
	Masayoshi MIZUMA <m.mizuma@...fujitsu.com>,
	Andreas Dilger <adilger.kernel@...ger.ca>,
	linux-ext4@...r.kernel.org, linux-fsdevel@...r.kernel.org
Subject: Re: [RFC][PATCH] Re: [BUG] ext4: cannot unfreeze a filesystem due
 to a deadlock

On 05/02/2011 03:20 PM, Jan Kara wrote:
> On Mon 02-05-11 14:27:51, Surbhi Palande wrote:
>> On 05/02/2011 01:56 PM, Jan Kara wrote:
>>> On Mon 02-05-11 12:07:59, Surbhi Palande wrote:
>>>> On 04/06/2011 02:21 PM, Dave Chinner wrote:
>>>>> On Wed, Apr 06, 2011 at 08:18:56AM +0200, Jan Kara wrote:
>>>>>> On Wed 06-04-11 15:40:05, Dave Chinner wrote:
>>>>>>> On Fri, Apr 01, 2011 at 04:08:56PM +0200, Jan Kara wrote:
>>>>>>>> On Fri 01-04-11 10:40:50, Dave Chinner wrote:
>>>>>>>>> If you don't allow the page to be dirtied in the fist place, then
>>>>>>>>> nothing needs to be done to the writeback path because there is
>>>>>>>>> nothing dirty for it to write back.
>>>>>>>>    Sure but that's only the problem he was able to hit. But generally,
>>>>>>>> there's a problem with needing s_umount for unfreezing because it isn't
>>>>>>>> clear there aren't other code paths which can block with s_umount held
>>>>>>>> waiting for fs to get unfrozen. And these code paths would cause the same
>>>>>>>> deadlock. That's why I chose to get rid of s_umount during thawing.
>>>>>>> Holding the s_umount lock while checking if frozen and sleeping
>>>>>>> is essentially an ABBA lock inversion bug that can bite in many more
>>>>>>> places that just thawing the filesystem.  Any where this is done should
>>>>>>> be fixed, so I don't think just removing the s_umount lock from the thaw
>>>>>>> path is sufficient to avoid problems.
>>>>>>    That's easily said but hard to do - any transaction start in ext3/4 may
>>>>>> block on filesystem being frozen (this seems to be similar for XFS as I'm
>>>>>> looking into the code) and transaction start traditionally nests inside
>>>>>> s_umount (and basically there's no way around that since sync() calls your
>>>>>> fs code with s_umount held).
>>>>> Sure, but the question must be asked - why is ext3/4 even starting a
>>>>> transaction on a clean filesystem during sync? A frozen filesystem,
>>>>> by definition, is a clean filesytem, and therefore sync calls of any
>>>>> kind should not be trying to write to the FS or start transactions.
>>>>> XFS does this just fine, so I'd consider such behaviour on a frozen
>>>>> filesystem a bug in ext3/4...
>>>> I had a look at the xfs code for seeing how this is done.
>>>> xfs_file_aio_write()
>>>>    xfs_wait_for_freeze()
>>>>      vfs_check_frozen()
>>>> So xfs_file_aio_write() writes to buffers when the FS is not frozen.
>>>>
>>>> Now, I want to know what stops the following scenario from happening:
>>>> --------------------
>>>> xfs_file_aio_write()
>>>>    xfs_wait_for_freeze()
>>>>      vfs_check_frozen()
>>>> At this point F.S was not frozen, so the next instruction in the
>>>> xfs_file_aio_write() will be executed next.
>>>> However at this point (i.e after checking if F.S is frozen) the
>>>> write process gets pre-empted and say the _freeze_ process gets
>>>> control.
>>>>
>>>> Now the F.S freezes and the write process gets the control back. And
>>>> so we end up writing to the page cache when the F.S is frozen.
>>>> --------------------
>>>>
>>>> Can anyone please enlighten me on how&   why this premption is _not_
>>>> possible?
>> Thanks for your reply.
>>>    XFS works similarly as ext4 in this regard I believe. They have the log
>>> frozen in xfs_freeze() so if the race you describe above happens, either
>>> the writing process gets caught waiting for log to unfreeze
>> Agreed.
>>>   or it manages
>>> to start a transaction and then freezing process waits for transaction to
>>> finish before it can proceed with freezing. I'm not sure why is there the
>>> check in xfs_file_aio_write()...
>>>
>>> 			
>> I am sorry, but I don't understand how this will happen - i.e I
>> can't understand what stops freeze_super() (or ext4_freeze) from
>> freezing a superblock (as the write process stopped just before
>> writing anything for this transaction and has not taken any locks?)
>    So ext4_freeze() does
> jbd2_journal_lock_updates(journal)
>    which waits for all running transactions to finish and updates
> j_barrier_count which stops any news ones from proceeding (check
> function start_this_handle()).
>
Yes, but ext4_freeze() also calls jbd2_journal_unlock_updates(journal) 
which decrements the  j_barrier_count (which was previously 
updated/incremented in jbd2_journal_lock_updates) ? before it returns. 
So after this call a new transaction/handle can be accepted/started.

A comment in ext4_freeze() says:
/* we rely on s_frozen to stop further updates */
(before calling jbd2_journal_unlock_updates())

Warm Regards,
Surbhi.
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