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Message-ID: <x49d3hck4lj.fsf@segfault.boston.devel.redhat.com>
Date: Thu, 14 Jul 2011 16:08:24 -0400
From: Jeff Moyer <jmoyer@...hat.com>
To: Jan Kara <jack@...e.cz>
Cc: Tao Ma <tm@....ma>, Vivek Goyal <vgoyal@...hat.com>,
linux-ext4@...r.kernel.org, stable@...nel.org,
Corrado Zoccolo <czoccolo@...il.com>,
Jens Axboe <jaxboe@...ionio.com>
Subject: Re: [PATCH] jbd/2[stable only]: Use WRITE_SYNC_PLUG in journal_commit_transaction.
Jan Kara <jack@...e.cz> writes:
> On Thu 14-07-11 12:30:32, Jeff Moyer wrote:
>> Tao Ma <tm@....ma> writes:
>> >> - WRITE_SYNC_PLUG will plug the queue and expects explicity unplug. Who
>> >> is doing unplug in this case?
>> > See the comments I removed, "we rely on sync_buffer() doing the unplug
>> > for us". I removed them cause we all use pluged write now.
>>
>> Your logic is upside-down. The code currently only uses the _PLUG
>> variant when t_synchronous_commit is set, meaning somebody *will* call
>> sync_buffer. Simply setting WRITE_SYNC_PLUG doens't mean the upper
>> layer is going to issue the unplug. Of course, I'm not 100% sure of the
>> journaling process, so it may very well be that there always is an
>> unplug. Can Jan or someone comment on that? Anyway, you could test
>> this theory by seeing if your kernel generates any timer unplugs in the
>> blktrace output.
> So I'm not expert in plugging code but from what I understand when we do
> wait_on_buffer() (which calls io_schedule()) which will do
> blk_flush_plug()), the queue will get unplugged and IO starts. And we wait
> for all buffers we submit so we are guaranteed wait_on_buffer() will be
> called...
Sorry, I should have been more specific. As Vivek mentioned, we're
talking about older kernels (pre the blk plugging series). So, the
question is, if journal_commit_transaction is called with
t_synchronous_commit not set, will the underlying device ever be
unplugged by the journal code? My guess is there's no explicit unplug,
so it's not correct to replace a WRITE_SYNC with a WRITE_SYNC_PLUG.
Cheers,
Jeff
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