linux-ext4 - exporting uuid_t from uapi/linux/uuid.h

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Date:   Tue, 21 Aug 2018 22:25:50 +0300
From:   Nikolay Borisov <nborisov@...e.com>
To:     linux-api@...r.kernel.org
Cc:     Ext4 Developers List <linux-ext4@...r.kernel.org>,
        linux-btrfs <linux-btrfs@...r.kernel.org>,
        Ted Ts'o <tytso@....edu>
Subject: exporting uuid_t from uapi/linux/uuid.h

Hello,

I'm doing some refactoring on btrfs and would like to convert some of
the "naked" definition of UUID in on-disk object to uuid_t. Since those
structs are defined in include/uapi/linux/btrfs_tree.h I naturally would
need to expose the kernel uuid_t to the uapi header via
include/uapi/linux/uuid.h. The uuid was originally unexported in
60927bc31436 ("uuid: remove uuid_be defintions from the uapi header")
 but at that time it was called uuid_be. The thing is that btrfs-progs
for example uses both btrfs_tree.h uapi header as well as libuuid. THe
latter also defines uuid_t. Both the kernel one and libuuid are binary
compatible.

So what's the correct way (if any) to expose a kernel type that might
have also been defined by a userspace library?

Regards,
Nikolay