linux-ext4 - Re: [PATCH 1/1] ext4: fix potential negative array index in do

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Message-Id: <9322DADB-8C6F-4595-AB6E-A92F627CDC82@dilger.ca>
Date:   Thu, 18 Jun 2020 18:33:50 -0600
From:   Andreas Dilger <adilger@...ger.ca>
To:     Eric Sandeen <sandeen@...hat.com>
Cc:     "linux-ext4@...r.kernel.org" <linux-ext4@...r.kernel.org>
Subject: Re: [PATCH 1/1] ext4: fix potential negative array index in
 do_split()

On Jun 17, 2020, at 1:19 PM, Eric Sandeen <sandeen@...hat.com> wrote:
> 
> If for any reason a directory passed to do_split() does not have enough
> active entries to exceed half the size of the block, we can end up
> iterating over all "count" entries without finding a split point.
> 
> In this case, count == move, and split will be zero, and we will
> attempt a negative index into map[].
> 
> Guard against this by detecting this case, and falling back to
> split-to-half-of-count instead; in this case we will still have
> plenty of space (> half blocksize) in each split block.
> 
> Fixes: ef2b02d3e617 ("ext34: ensure do_split leaves enough free space in both blocks")
> Signed-off-by: Eric Sandeen <sandeen@...hat.com>

Reviewed-by: Andreas Dilger <adilger@...ger.ca>

> ---
> 
> diff --git a/fs/ext4/namei.c b/fs/ext4/namei.c
> index a8aca4772aaa..8b60881f07ee 100644
> --- a/fs/ext4/namei.c
> +++ b/fs/ext4/namei.c
> @@ -1858,7 +1858,7 @@ static struct ext4_dir_entry_2 *do_split(handle_t *handle, struct inode *dir,
> 			     blocksize, hinfo, map);
> 	map -= count;
> 	dx_sort_map(map, count);
> -	/* Split the existing block in the middle, size-wise */
> +	/* Ensure that neither split block is over half full */
> 	size = 0;
> 	move = 0;
> 	for (i = count-1; i >= 0; i--) {
> @@ -1868,8 +1868,18 @@ static struct ext4_dir_entry_2 *do_split(handle_t *handle, struct inode *dir,
> 		size += map[i].size;
> 		move++;
> 	}
> -	/* map index at which we will split */
> -	split = count - move;
> +	/*
> +	 * map index at which we will split
> +	 *
> +	 * If the sum of active entries didn't exceed half the block size, just
> +	 * split it in half by count; each resulting block will have at least
> +	 * half the space free.
> +	 */
> +	if (i > 0)
> +		split = count - move;
> +	else
> +		split = count/2;
> +
> 	hash2 = map[split].hash;
> 	continued = hash2 == map[split - 1].hash;
> 	dxtrace(printk(KERN_INFO "Split block %lu at %x, %i/%i\n",
> 
> 


Cheers, Andreas






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