linux-hardening - [PATCH 11/38] docs: kdoc_parser: fix parser to support multi-word types

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Message-ID: <35ed0e29955ab12d67e22d451d03c7cf0a3530c3.1771408406.git.mchehab+huawei@kernel.org>
Date: Wed, 18 Feb 2026 11:12:41 +0100
From: Mauro Carvalho Chehab <mchehab+huawei@...nel.org>
To: Jonathan Corbet <corbet@....net>,
	Linux Doc Mailing List <linux-doc@...r.kernel.org>
Cc: Mauro Carvalho Chehab <mchehab+huawei@...nel.org>,
	intel-wired-lan@...ts.osuosl.org,
	linux-hardening@...r.kernel.org,
	linux-kernel@...r.kernel.org,
	netdev@...r.kernel.org,
	Aleksandr Loktionov <aleksandr.loktionov@...el.com>,
	Randy Dunlap <rdunlap@...radead.org>
Subject: [PATCH 11/38] docs: kdoc_parser: fix parser to support multi-word types

The regular expression currently expects a single word for the
type, but it may be something like  "struct foo".

Add support for it.

Signed-off-by: Mauro Carvalho Chehab <mchehab+huawei@...nel.org>
Acked-by: Randy Dunlap <rdunlap@...radead.org>
Tested-by: Randy Dunlap <rdunlap@...radead.org>
Reviewed-by: Aleksandr Loktionov <aleksandr.loktionov@...el.com>
---
 tools/lib/python/kdoc/kdoc_parser.py | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/tools/lib/python/kdoc/kdoc_parser.py b/tools/lib/python/kdoc/kdoc_parser.py
index d8e96c6c4ebc..f524385543a6 100644
--- a/tools/lib/python/kdoc/kdoc_parser.py
+++ b/tools/lib/python/kdoc/kdoc_parser.py
@@ -1027,7 +1027,7 @@ class KernelDoc:
 
         default_val = None
 
-        r= KernRe(OPTIONAL_VAR_ATTR + r"[\w_]*\s+(?:\*+)?([\w_]+)\s*[\d\]\[]*\s*(=.*)?")
+        r= KernRe(OPTIONAL_VAR_ATTR + r"\s*[\w_\s]*\s+(?:\*+)?([\w_]+)\s*[\d\]\[]*\s*(=.*)?")
         if r.match(proto):
             if not declaration_name:
                 declaration_name = r.group(1)
@@ -1038,7 +1038,7 @@ class KernelDoc:
                                   r.groups(), proto)
 
         else:
-            r= KernRe(OPTIONAL_VAR_ATTR + r"(?:[\w_]*)?\s+(?:\*+)?(?:[\w_]+)\s*[\d\]\[]*\s*(=.*)?")
+            r= KernRe(OPTIONAL_VAR_ATTR + r"(?:[\w_\s]*)?\s+(?:\*+)?(?:[\w_]+)\s*[\d\]\[]*\s*(=.*)?")
 
             if r.match(proto):
                 default_val = r.group(1)
-- 
2.52.0