linux-kernel - Re: Serial custom speed deprecated?

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Message-ID: <87hczwkbcc.fsf@graviton.dyn.troilus.org>
Date:	Mon, 28 Aug 2006 13:40:35 -0400
From:	Michael Poole <mdpoole@...ilus.org>
To:	"linux-os \(Dick Johnson\)" <linux-os@...logic.com>
Cc:	"Alan Cox" <alan@...rguk.ukuu.org.uk>, <linux@...izon.com>,
	<linux-kernel@...r.kernel.org>
Subject: Re: Serial custom speed deprecated?

linux-os \(Dick Johnson\) writes:

> On Mon, 28 Aug 2006, Michael Poole wrote:
>
>> What baud rate does your system define CBAUDEX | B0 to be?  On my
>
> B0 is 0 (zero), no bits. If you are trying to play semantic games and
> claim B0 is 1, i.e., bit 0, then it would not be written as B0, it
> would be written as B(0) or B:0. B0 is defined to be the baud-rate
> used to hang up the modem. It is zero in all bits on most all
> implementations including my Sun. On most recent Linux distributions,
> CBAUDEX is (octal) 0010000. Since B0 is zero, ORing it into CBAUDEX
> does nothing.

Thanks, Sherlock!  Again: What does CBAUDEX, by itself, do on your
system?  As Alan Cox obviously thought the rest of the world was
bright enough to notice, and as I tried to explain, the CBAUDEX bit is
currently not defined when set by itself (i.e. as if it were CBAUDEX,
CBAUDEX | B0, CBAUDEX << 0 or however else you want to denote it);
there is always some other low-order (CBAUD) bit associated with it:

>> AMD64 machine, both the x86-64 and i386 asm/termbits.h files skip
>> CBAUDEX -- B38400 is 0000017 and B57600 is 0010001 (CBAUDEX | B50).
>> The headers do not define any baud rate between those two, either by
>> rate or by c_cflag value.

Michael Poole
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