linux-kernel - Re: How much kernel memory is in 64-bit OS ?

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Message-ID: <Pine.LNX.4.61.0609181430530.30064@yvahk01.tjqt.qr>
Date:	Mon, 18 Sep 2006 14:34:25 +0200 (MEST)
From:	Jan Engelhardt <jengelh@...ux01.gwdg.de>
To:	Rik van Riel <riel@...hat.com>
cc:	yogeshwar sonawane <yogyas@...il.com>,
	linux-kernel <linux-kernel@...r.kernel.org>
Subject: Re: How much kernel memory is in 64-bit OS ?


>> > Sure, people said that too when going from 16 bits to 32 bits,
>> > but that was only a factor 2^16 difference.  This time it's the
>> > square of the previous difference.
>> 
>> Not quite the square :)
>
> 2^32 is the square of 2^16 :)

Going from 32 to 64:   (2^64 - 2^32)
Going from 16 to 32:   (2^32 - 2^16)

As mentioned above, "the square of the previos" [16 to 32] "difference". 
Call me nitpicky, but:

(2^32 - 2^16)^2  !=  (2^64 - 2^32)

>-- 
> What is important?  What you want to be true, or what is true?


Jan Engelhardt
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