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Date:	Wed, 30 May 2007 10:31:06 +0200 (MEST)
From:	Jan Engelhardt <jengelh@...ux01.gwdg.de>
To:	Nitin Gupta <nitingupta910@...il.com>
cc:	lkml <linux-kernel@...r.kernel.org>, linux-mm-cc@...top.org,
	linuxcompressed-devel@...ts.sourceforge.net,
	Andrew Morton <akpm@...ux-foundation.org>,
	Daniel Hazelton <dhazelton@...er.net>,
	Richard Purdie <richard@...nedhand.com>,
	Bret Towe <magnade@...il.com>,
	Satyam Sharma <satyam.sharma@...il.com>
Subject: Re: [RFC] LZO de/compression support - take 6


On May 30 2007 11:24, Nitin Gupta wrote:
>> 
>> It is the bytestream (ip) that is reinterpreted as uint16_t.
>> And I really doubt that the LZO author has a big-endian machine,
>> given the days of ubiquitous x86.
>
>> le16_to_cpu it is.
>
> But then why you think it should be
> le_16_cpu() -- how will this make any difference?

Like I said, we are reinterpreting the byte stream as a uint16_t
(= reading from bytestream to CPU). While writing out an uint16_t
as a bytestream is cpu_to_le16.

> For your ref (from big_endian.h):
> # define __cpu_to_le16(x) ((__force __le16)__swab16((x)))
> # define __le16_to_cpu(x) __swab16((__force __u16)(__le16)(x))


	Jan
-- 
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