linux-kernel - Re: workqueue is not working?

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Message-ID: <11706967.post@talk.nabble.com>
Date:	Sun, 22 Jul 2007 20:56:17 -0700 (PDT)
From:	Misbah khan <misbah_khan@...ineer.com>
To:	linux-kernel@...r.kernel.org
Subject: Re: workqueue is not working?


I didnt got very clearly what you actually did. But i guess you did faced
some problem to work with work queue ( Bottom half of the handler ) I
suggest you with an example code so that you could try with it and hope your
doubt would get cleared.

/* work queue register and initialize */
static DECLARE_WORK(queue_name,(void *)func_name,func_arq_ptr);

eg :-

static DECLARE_WORK(my_queue,(void *)my_func,NULL);

/* In the Interrupt handler you need to call the bottom half of the function
*/

schedule_work(&my_queue);

/* The function defination is like this */
void my_func(void)
{
       printk(" Hello from kernal land \n");
}

I hope this example will make your code to work for you , for any
clarification please let me know 

thanks 




Xin Zhao wrote:
> 
> I tried to schedule some work in an softirq handler. The way I did is
> as follows:
> 
> I use create_workqueue to initialize a workqueue "vrpciod_workqueue",
> 
> in the softirq, I do INIT_WORK(work, func, data), and then
> queue_work(vrpciod_workqueue, work);
> 
> I think func() should be called a bit later. However, I noticed that
> func() is never called by the workqueue. I don't know why.
> 
> Can soneone give me some suggestions? Many thanks!
> 
> Xin
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