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Message-ID: <loom.20070927T061840-329@post.gmane.org>
Date: Thu, 27 Sep 2007 06:26:15 +0000 (UTC)
From: Shreyansh Jain <shreyansh.jain@...il.com>
To: linux-kernel@...r.kernel.org
Subject: Re: try_module_get code understanding
Thanks for you reply, please see inline.
Heiko Carstens <heiko.carstens <at> de.ibm.com> writes:
>
[snip]
> > static inline int try_module_get(struct module *module){
> > int ret = 1; <--- error case when !module
> > if (module) {
> > unsigned int cpu = get_cpu();
> > if (likely(module_is_live(module)))
> > local_inc(&module->ref[cpu].count);
> > else
> > ret = 0; <--- error case
> > put_cpu();
> > }
> > return ret; <----
> > }
> > ----
[snip]
> Somewhere in module.h you have:
>
> #ifdef MODULE
> #define THIS_MODULE (&__this_module)
> #else /* !MODULE */
> #define THIS_MODULE ((struct module *)0)
> #endif
>
> So this just means, that THIS_MODULE is NULL for compiled in modules
> and therefore try_module_get(NULL) succeeds. It's not an error case.
Agreed.
Then what is return value if my module tries to 'get' a module which does not
exist (and is a module, not in-built)? . Is it '1' ?
Or am I imagining a hypothetical scenario which would not exist?
Thanks again for your fast response.
Shreyansh
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