linux-kernel - Re: [PATCH RFC 3/9] RCU: Preemptible RCU

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Message-ID: <Pine.LNX.4.64.0710011129440.25942@alien.or.mcafeemobile.com>
Date:	Mon, 1 Oct 2007 11:44:25 -0700 (PDT)
From:	Davide Libenzi <davidel@...ilserver.org>
To:	"Paul E. McKenney" <paulmck@...ux.vnet.ibm.com>
cc:	Oleg Nesterov <oleg@...sign.ru>,
	Linux Kernel Mailing List <linux-kernel@...r.kernel.org>,
	linux-rt-users@...r.kernel.org, Ingo Molnar <mingo@...e.hu>,
	Andrew Morton <akpm@...ux-foundation.org>, dipankar@...ibm.com,
	josht@...ux.vnet.ibm.com, tytso@...ibm.com, dvhltc@...ibm.com,
	tglx@...utronix.de, a.p.zijlstra@...llo.nl, bunk@...nel.org,
	ego@...ibm.com, srostedt@...hat.com
Subject: Re: [PATCH RFC 3/9] RCU: Preemptible RCU

On Sun, 30 Sep 2007, Paul E. McKenney wrote:

> On Sun, Sep 30, 2007 at 04:02:09PM -0700, Davide Libenzi wrote:
> > On Sun, 30 Sep 2007, Oleg Nesterov wrote:
> > 
> > > Ah, but I asked the different question. We must see CPU 1's stores by
> > > definition, but what about CPU 0's stores (which could be seen by CPU 1)?
> > > 
> > > Let's take a "real life" example,
> > > 
> > >                 A = B = X = 0;
> > >                 P = Q = &A;
> > > 
> > > CPU_0           CPU_1           CPU_2
> > > 
> > > P = &B;         *P = 1;         if (X) {
> > >                 wmb();                  rmb();
> > >                 X = 1;                  BUG_ON(*P != 1 && *Q != 1);
> > >                                 }
> > > 
> > > So, is it possible that CPU_1 sees P == &B, but CPU_2 sees P == &A ?
> > 
> > That can't be. CPU_2 sees X=1, that happened after (or same time at most - 
> > from a cache inv. POV) to *P=1, that must have happened after P=&B (in 
> > order for *P to assign B). So P=&B happened, from a pure time POV, before 
> > the rmb(), and the rmb() should guarantee that CPU_2 sees P=&B too.
> 
> Actually, CPU designers have to go quite a ways out of their way to
> prevent this BUG_ON from happening.  One way that it would happen
> naturally would be if the cache line containing P were owned by CPU 2,
> and if CPUs 0 and 1 shared a store buffer that they both snooped.  So,
> here is what could happen given careless or sadistic CPU designers:

Ohh, I misinterpreted that rmb(), sorry. Somehow I gave it for granted
that it was a cross-CPU sync point (ala read_barrier_depends). If that's a
local CPU load ordering only, things are different, clearly. But ...



> 
> o	CPU 0 stores &B to P, but misses the cache, so puts the
> 	result in the store buffer.  This means that only CPUs 0 and 1
> 	can see it.
> 
> o	CPU 1 fetches P, and sees &B, so stores a 1 to B.  Again,
> 	this value for P is visible only to CPUs 0 and 1.
> 
> o	CPU 1 executes a wmb(), which forces CPU 1's stores to happen
> 	in order.  But it does nothing about CPU 0's stores, nor about CPU
> 	1's loads, for that matter (and the only reason that POWER ends
> 	up working the way you would like is because wmb() turns into
> 	"sync" rather than the "eieio" instruction that would have been
> 	used for smp_wmb() -- which is maybe what Oleg was thinking of,
> 	but happened to abbreviate.  If my analysis is buggy, Anton and
> 	Paulus will no doubt correct me...)

If a store buffer is shared between CPU_0 and CPU_1, it is very likely 
that a sync done on CPU_1 is going to sync even CPU_0 stores that are 
held in the buffer at the time of CPU_1's sync.



- Davide


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