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Message-ID: <20071122091732.02d73217@laptopd505.fenrus.org>
Date: Thu, 22 Nov 2007 09:17:32 -0800
From: Arjan van de Ven <arjan@...radead.org>
To: "Leon Woestenberg" <leon.woestenberg@...il.com>
Cc: linux-kernel@...r.kernel.org
Subject: Re: Use of mutex in interrupt context flawed/impossible, need
advice.
On Thu, 22 Nov 2007 17:02:44 +0100
"Leon Woestenberg" <leon.woestenberg@...il.com> wrote:
> Hello,
>
>
> I'm converting an out-of-tree (*1) driver from binary semaphore to
> mutex.
>
> Userspace updates a look-up-table using write(). The driver tries to
> write this LUT to the FPGA in the (video frame) interrupt handler. It
> is important that the LUT is consistent and thus changed atomically.
> Note that it is not important that the LUT is updated each interrupt.
>
> The current approach is to try-down()ing a binary semaphore in
> interrupt context, and write the LUT to the FPGA if the semaphore was
> down()ed, do nothing else.
> The write() down()s the semaphore as well before updating the
> in-driver-copy of the LUT, then up()s it again.
>
> I understand this design is not clean (*2), and not even possible with
> mutexes, as mutex_trylock() is not interrupt safe.
>
> My current approach would be to have userspace write into a shadow
> copy, and use a spinlock to update the live copy. The interrupt then
> would try a spinlock.
>
I suspect you need to copy the userspace data anyway, so I don't see
why the spinlock approach would be wrong; if the update itself is short
and non-sleeping, it's even better than a mutex or semaphore.
--
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