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Message-ID: <Pine.LNX.4.64.0805201716160.25111@visualserver.org>
Date: Tue, 20 May 2008 17:25:29 +0200 (CEST)
From: Soumyadip Das Mahapatra <kernelhacker@...ualserver.org>
To: Akinobu Mita <akinobu.mita@...il.com>
cc: Harvey Harrison <harvey.harrison@...il.com>,
linux-kernel@...r.kernel.org
Subject: Re: [PATCH 1/2] bitreversal program
Thanks for giving a reply Akinobu :-)
I forgot that bitrev8() is static in header file. Sorry for that.
Below is my new patch considering this. Cant it be applicable?
Please review it.
I know that my bitrev8() takes more instructions than that
of yours. But we have to think about faster access of cpu cache over that
of memory cache(which your bit_rev_table uses).
Thanks anyway ;-)
---Inline Attachment---
--- a/include/linux/bitrev.h 2008-04-17 08:19:44.000000000 +0530
+++ b/include/linux/bitrev.h 2008-05-20 20:41:13.000000000 +0530
@@ -3,11 +3,49 @@
#include <linux/types.h>
-extern u8 const byte_rev_table[256];
+/**
+ * Here is a generalised bit reversal program
+ * @x: word to get bits reversed
+ * @k: key, explained below
+ * for k = 31, it reverses the bits of word(32 bit)
+ * for k = 24, it reverses the bytes in word
+ * for k = 7, it reverses the bits in every byte without
+ * changing the positions of bytes in a word
+ * and for k = 16 it swaps the left and right halves of a
+ * word
+ */
+
+static inline u32 gen_bit_rev(u32 x, u32 k)
+{
+ if(k & 1)
+ x = (x & 0x55555555) << 1 | (x & 0xaaaaaaaa) >> 1;
+ if(k & 2)
+ x = (x & 0x33333333) << 2 | (x & 0xcccccccc) >> 2;
+ if(k & 4)
+ x = (x & 0x0f0f0f0f) << 4 | (x & 0xf0f0f0f0) >> 4;
+ if(k & 8)
+ x = (x & 0x00ff00ff) << 8 | (x & 0xff00ff00) >> 8;
+ if(k & 16)
+ x = (x & 0x0000ffff) << 16 | (x & 0xffff0000) >> 16;
+
+ return x;
+}
+
+/**
+ * bitrev8(): function for reversing bits of a byte
+ * @byte: the byte to get its bits reversed
+ */
static inline u8 bitrev8(u8 byte)
{
- return byte_rev_table[byte];
+ u8 k = 7;
+ if(k & 1)
+ byte = (byte & 0x5555) << 1 | (byte & 0xaaaa) >> 1;
+ if(k & 2)
+ byte = (byte & 0x3333) << 2 | (byte & 0xcccc) >> 2;
+ if(k & 4)
+ byte = (byte & 0x0f0f) << 4 | (byte & 0xf0f0) >> 4;
+ return byte;
}
extern u32 bitrev32(u32 in);
--
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