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Date:	Thu, 6 Nov 2008 01:20:29 +0900 (JST)
From:	"KAMEZAWA Hiroyuki" <kamezawa.hiroyu@...fujitsu.com>
To:	balbir@...ux.vnet.ibm.com
Cc:	"KAMEZAWA Hiroyuki" <kamezawa.hiroyu@...fujitsu.com>,
	linux-mm@...ck.org, "YAMAMOTO Takashi" <yamamoto@...inux.co.jp>,
	"Paul Menage" <menage@...gle.com>, lizf@...fujitsu.com,
	linux-kernel@...r.kernel.org,
	"Nick Piggin" <nickpiggin@...oo.com.au>,
	"David Rientjes" <rientjes@...gle.com>,
	"Pavel Emelianov" <xemul@...nvz.org>,
	"Dhaval Giani" <dhaval@...ux.vnet.ibm.com>,
	"Andrew Morton" <akpm@...ux-foundation.org>
Subject: Re: [mm] [PATCH 3/4] Memory cgroup hierarchical reclaim

Balbir Singh said:
>>>>> +	list_for_each_entry_safe_from(cgroup, cg,
>>>>> &cg_current->parent->children,
>>>>> +						 sibling) {
>>>>> +		mem_child = mem_cgroup_from_cont(cgroup);
>>>>> +
>>>>> +		/*
>>>>> +		 * Move beyond last scanned child
>>>>> +		 */
>>>>> +		if (mem_child == mem->last_scanned_child)
>>>>> +			continue;
>>>>> +
>>>>> +		ret = try_to_free_mem_cgroup_pages(mem_child, gfp_mask);
>>>>> +		mem->last_scanned_child = mem_child;
>>>>> +
>>>>> +		if (res_counter_check_under_limit(&mem->res)) {
>>>>> +			ret = 0;
>>>>> +			goto done;
>>>>> +		}
>>>>> +	}
>>>> Is this safe against cgroup create/remove ? cgroup_mutex is held ?
>>> Yes, I thought about it, but with the setup, each parent will be busy
>>> since they
>>> have children and hence cannot be removed. The leaf child itself has
>>> tasks, so
>>> it cannot be removed. IOW, it should be safe against removal.
>>>
>> I'm sorry if I misunderstand something. could you explain folloing ?
>>
>> In following tree,
>>
>>     level-1
>>          -  level-2
>>                 -  level-3
>>                        -  level-4
>> level-1's usage = level-1 + level-2 + level-3 + level-4
>> level-2's usage = level-2 + level-3 + level-4
>> level-3's usage = level-3 + level-4
>> level-4's usage = level-4
>>
>> Assume that a task in level-2 hits its limit. It has to reclaim memory
>> from
>> level-2 and level-3, level-4.
>>
>> How can we guarantee level-4 has a task in this case ?
>
> Good question. If there is no task, the LRU's will be empty and reclaim
> will
> return. We could also add other checks if needed.
>
If needed ?, yes, you need.
The problem is that you are walking a list in usual way without any lock
or guarantee that the list will never be modified.

My quick idea is following.
==
Before start reclaim.
 1. take lock_cgroup()
 2. scan the tree and create "private" list as snapshot of tree to be
    scanned.
 3. unlock_cgroup().
 4. start reclaim.

Adding refcnt to memcg to delay freeing memcg control area is necessary.
(mem+swap controller have function to do this and you may be able to
 reuse it.)

Thanks,
-Kame


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