linux-kernel - Re: [PATCH 2/3] ftrace: use struct pid

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Message-Id: <1228396022.13111.27.camel@nimitz>
Date:	Thu, 04 Dec 2008 05:07:02 -0800
From:	Dave Hansen <dave@...ux.vnet.ibm.com>
To:	"Eric W. Biederman" <ebiederm@...ssion.com>
Cc:	Frederic Weisbecker <fweisbec@...il.com>,
	linux-kernel@...r.kernel.org, Steven Rostedt <rostedt@...dmis.org>,
	Steven Rostedt <srostedt@...hat.com>,
	containers@...ts.osdl.org, Ingo Molnar <mingo@...e.hu>,
	Sukadev Bhattiprolu <sukadev@...ux.vnet.ibm.com>,
	Andrew Morton <akpm@...ux-foundation.org>
Subject: Re: [PATCH 2/3] ftrace: use struct pid

On Thu, 2008-12-04 at 04:56 -0800, Dave Hansen wrote:
> On Thu, 2008-12-04 at 04:42 -0800, Eric W. Biederman wrote:
> > 
> > > +static void clear_ftrace_pid_task(struct pid **pid)
> > > +{
> > > +     struct task_struct *p;
> > > +
> >         rcu_read_lock();
> > 
> > > +     do_each_pid_task(*pid, PIDTYPE_PID, p) {
> > > +             clear_tsk_trace_trace(p);
> > > +     } while_each_pid_task(*pid, PIDTYPE_PID, p);
> >         rcu_read_unlock()
> > 
> > > +     put_pid(*pid);
> > > +
> > > +     *pid = NULL;
> > > +}
> 
> Could we get away with sticking the rcu_read_{un}lock() inside those
> macros?  Those are going to get used in pretty high level code and we're
> allowed to nest rcu_read_lock().  No danger of deadlocks or lock
> inversions.

Why don't any of the other users of do_each_pid_task() use
rcu_read_lock()?  They all seem to be under read_lock(&tasklist_lock)
(except one is under a write lock of the same).

-- Dave

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