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Message-ID: <20081205031736.GA5265@in.ibm.com>
Date: Fri, 5 Dec 2008 08:47:36 +0530
From: Dipankar Sarma <dipankar@...ibm.com>
To: Dave Hansen <dave@...ux.vnet.ibm.com>
Cc: "Eric W. Biederman" <ebiederm@...ssion.com>,
Frederic Weisbecker <fweisbec@...il.com>,
linux-kernel@...r.kernel.org, Steven Rostedt <rostedt@...dmis.org>,
Steven Rostedt <srostedt@...hat.com>,
containers@...ts.osdl.org, Ingo Molnar <mingo@...e.hu>,
Sukadev Bhattiprolu <sukadev@...ux.vnet.ibm.com>,
Andrew Morton <akpm@...ux-foundation.org>
Subject: Re: [PATCH 2/3] ftrace: use struct pid
On Thu, Dec 04, 2008 at 05:07:02AM -0800, Dave Hansen wrote:
> On Thu, 2008-12-04 at 04:56 -0800, Dave Hansen wrote:
> > On Thu, 2008-12-04 at 04:42 -0800, Eric W. Biederman wrote:
> > >
> > > > +static void clear_ftrace_pid_task(struct pid **pid)
> > > > +{
> > > > + struct task_struct *p;
> > > > +
> > > rcu_read_lock();
> > >
> > > > + do_each_pid_task(*pid, PIDTYPE_PID, p) {
> > > > + clear_tsk_trace_trace(p);
> > > > + } while_each_pid_task(*pid, PIDTYPE_PID, p);
> > > rcu_read_unlock()
> > >
> > > > + put_pid(*pid);
> > > > +
> > > > + *pid = NULL;
> > > > +}
> >
> > Could we get away with sticking the rcu_read_{un}lock() inside those
> > macros? Those are going to get used in pretty high level code and we're
> > allowed to nest rcu_read_lock(). No danger of deadlocks or lock
> > inversions.
>
> Why don't any of the other users of do_each_pid_task() use
> rcu_read_lock()? They all seem to be under read_lock(&tasklist_lock)
> (except one is under a write lock of the same).
The pid hash list is protected by tasklist_lock, right ? If so,
holding read_lock(&tasklist_lock) will make this safe, you don't
need rcu_read_lock/unlock(). This isn't a lock-free reader.
Thanks
Dipankar
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