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Message-ID: <20090123095904.GA22890@cmpxchg.org>
Date: Fri, 23 Jan 2009 10:59:04 +0100
From: Johannes Weiner <hannes@...xchg.org>
To: Oleg Nesterov <oleg@...hat.com>
Cc: Chris Mason <chris.mason@...cle.com>,
Peter Zijlstra <a.p.zijlstra@...llo.nl>,
Matthew Wilcox <matthew@....cx>,
Chuck Lever <cel@...i.umich.edu>,
Nick Piggin <nickpiggin@...oo.com.au>,
Andrew Morton <akpm@...ux-foundation.org>,
linux-kernel@...r.kernel.org, linux-mm@...ck.org,
Ingo Molnar <mingo@...e.hu>
Subject: Re: [RFC v4] wait: prevent waiter starvation in __wait_on_bit_lock
On Thu, Jan 22, 2009 at 09:25:50PM +0100, Oleg Nesterov wrote:
> On 01/21, Johannes Weiner wrote:
> >
> > @@ -187,6 +187,31 @@ __wait_on_bit_lock(wait_queue_head_t *wq, struct wait_bit_queue *q,
> > }
> > } while (test_and_set_bit(q->key.bit_nr, q->key.flags));
> > finish_wait(wq, &q->wait);
> > + if (unlikely(ret)) {
> > + /*
> > + * Contenders are woken exclusively. If we were woken
> > + * by an unlock we have to take the lock ourselves and
> > + * wake the next contender on unlock. But the waiting
> > + * function failed, we do not take the lock and won't
> > + * unlock in the future. Make sure the next contender
> > + * does not wait forever on an unlocked bit.
> > + *
> > + * We can also get here without being woken through
> > + * the waitqueue, so there is a small chance of doing a
> > + * bogus wake up between an unlock clearing the bit and
> > + * the next contender being woken up and setting it again.
> > + *
> > + * It does no harm, though, the scheduler will ignore it
> > + * as the process in question is already running.
> > + *
> > + * The unlock path clears the bit and then wakes up the
> > + * next contender. If the next contender is us, the
> > + * barrier makes sure we also see the bit cleared.
> > + */
> > + smp_rmb();
> > + if (!test_bit(q->key.bit_nr, q->key.flags)))
> > + __wake_up_bit(wq, q->key.flags, q->key.bit_nr);
>
> I think this is correct, and (unfortunately ;) you are right:
> we need rmb() even after finish_wait().
>
> And we have to check ret twice, and the false wakeup is still
> possible. This is minor, but just for discussion, can't we do
> this differently?
>
> int finish_wait_xxx(wait_queue_head_t *q, wait_queue_t *wait)
> {
> unsigned long flags;
> int woken;
>
> __set_current_state(TASK_RUNNING);
> spin_lock_irqsave(&q->lock, flags);
> woken = list_empty(&wait->task_list);
> list_del_init(&wait->task_list);
> spin_unlock_irqrestore(&q->lock, flags);
>
> return woken;
> }
Hehe, there is only n solutions to this problem. I had thought about
that too, even written it down. But I was not sure if taking the
spinlock, toggling irqs and (re)storing the flags is better than an
untaken branch. ;)
> Now, __wait_on_bit_lock() does:
>
> if (test_bit(q->key.bit_nr, q->key.flags)) {
> if ((ret = (*action)(q->key.flags))) {
> if (finish_wait_xxx(...))
> __wake_up_bit(...);
> return ret;
> }
> }
If you don't mind putting a second finish_wait() in there (you still
need the one after the loop, right?), we can fix up my version to not
check ret twice but do finish_wait() as you describe and then the
test_bit() && wake up:
do {
if (test_bit())
if ((ret = action())) {
finish_wait()
smp_rmb()
if (!test_bit())
__wake_up_bit()
return ret
}
}
} while (test_and_set_bit())
finish_wait()
return 0
> Or we can introduce
>
> int finish_wait_yyy(wait_queue_head_t *q, wait_queue_t *wait,
> int mode, void *key)
> {
> unsigned long flags;
> int woken;
>
> __set_current_state(TASK_RUNNING);
> spin_lock_irqsave(&q->lock, flags);
> woken = list_empty(&wait->task_list);
> if (woken)
> __wake_up_common(q, mode, 1, key);
> else
> list_del_init(&wait->task_list);
> spin_unlock_irqrestore(&q->lock, flags);
>
> return woken;
> }
>
> Perhaps a bit too much for this particular case, but I am thinking
> about other cases when we need to abort the exclusive wait.
>
> For example, don't we have the similar problems with
> wait_event_interruptible_exclusive() ?
Yeah, we do IIUC. Then having finish_wait() extended is probably a
good idea.
> Oleg.
Hannes
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