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Message-ID: <alpine.DEB.1.10.0902091342000.14528@gandalf.stny.rr.com>
Date: Mon, 9 Feb 2009 13:43:04 -0500 (EST)
From: Steven Rostedt <rostedt@...dmis.org>
To: Eduard - Gabriel Munteanu <eduard.munteanu@...ux360.ro>
cc: Pekka Enberg <penberg@...helsinki.fi>,
linux-kernel@...r.kernel.org, Ingo Molnar <mingo@...e.hu>,
Andrew Morton <akpm@...ux-foundation.org>,
Frederic Weisbecker <fweisbec@...il.com>,
Steven Rostedt <srostedt@...hat.com>
Subject: Re: [PATCH 3/3] tracing: clean up splice code
On Mon, 9 Feb 2009, Eduard - Gabriel Munteanu wrote:
> On Mon, Feb 09, 2009 at 08:26:20PM +0200, Pekka Enberg wrote:
> > Eduard - Gabriel Munteanu wrote:
> >>> @@ -2573,45 +2607,25 @@ static ssize_t tracing_splice_read_pipe(struct
> >>> file *filp,
> >>> ret = iter->trace->splice_read(iter, filp,
> >>> ppos, pipe, len, flags);
> >>> if (ret)
> >>> - goto out;
> >>> + goto out_err;
> >>> }
> >>> ret = tracing_wait_pipe(filp);
> >>> if (ret <= 0)
> >>> - goto out;
> >>> + goto out_err;
> >>> if (!iter->ent && !find_next_entry_inc(iter)) {
> >>> ret = -EFAULT;
> >>> - goto out;
> >>> + goto out_err;
> >>> }
> >>> /* Fill as many pages as possible. */
> >>> for (i = 0, rem = len; i < PIPE_BUFFERS && rem; i++) {
> >>> pages[i] = alloc_page(GFP_KERNEL);
> >>> + if (!pages[i])
> >>> + break;
> >> I believe you should decrement 'i' before breaking, since we fill
> >> spd.nr_pages just after the loop. In case the current page couldn't be
> >> allocated, spd.nr_pages will be one too many (that is, 'i').
> >
> > But, but, if we fail for i == 1, for example, we want ->nr_pages == 1, no?
> >
> > Pekka
>
> Sure, my bad. I even made the same assumption myself about the outer
> 'for' loop when I wrote it ('i' would end up last page + 1). The patch is
> okay. :-)
Heh, I was just about to say, if this is wrong then so is the if below it
;-)
pages[i] = alloc_page(GFP_KERNEL);
if (!pages[i])
break;
rem = tracing_fill_pipe_page(pages[i], rem, iter);
/* Copy the data into the page, so we can start over. */
ret = trace_seq_to_buffer(&iter->seq,
page_address(pages[i]),
iter->seq.len);
if (ret < 0) {
__free_page(pages[i]);
Same 'i'.
break;
}
Thanks Eduard!
-- Steve
--
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