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Message-Id: <20090227095856.ef8c1c05.kamezawa.hiroyu@jp.fujitsu.com>
Date: Fri, 27 Feb 2009 09:58:56 +0900
From: KAMEZAWA Hiroyuki <kamezawa.hiroyu@...fujitsu.com>
To: paulmck@...ux.vnet.ibm.com
Cc: Peter Zijlstra <a.p.zijlstra@...llo.nl>,
Bharata B Rao <bharata.rao@...il.com>,
Li Zefan <lizf@...fujitsu.com>, Ingo Molnar <mingo@...e.hu>,
Paul Menage <menage@...gle.com>,
Balbir Singh <balbir@...ux.vnet.ibm.com>,
LKML <linux-kernel@...r.kernel.org>
Subject: Re: [PATCH] cpuacct: add a branch prediction
On Thu, 26 Feb 2009 08:45:09 -0800
"Paul E. McKenney" <paulmck@...ux.vnet.ibm.com> wrote:
> On Thu, Feb 26, 2009 at 09:06:24PM +0900, KAMEZAWA Hiroyuki wrote:
> > Peter Zijlstra wrote:
> > > On Thu, 2009-02-26 at 20:17 +0900, KAMEZAWA Hiroyuki wrote:
> > >> Peter Zijlstra wrote:
> > >> > On Thu, 2009-02-26 at 19:28 +0900, KAMEZAWA Hiroyuki wrote:
> > >> >
> > >> >> Taking hierarchy mutex while reading will make read-side stable.
> > >> >
> > >> > We're talking about scheduling here, taking a mutex to stop scheduling
> > >> > won't work, nor will it be acceptible to use anything that will.
> > >> >
> > >> No mutex is necessary, anyway.
> > >> hierarchy-walker function completely works well under rcu read lock,
> > >> if small jitter is allowed.
> > >
> > > Right, should be doable -- and looking at the code, we have this
> > > horrible 32 bit exception in there that locks the rq in order to read
> > > the 64bit value.
> > >
> > > Would be grand to get rid of that,. how bad would it be for userspace to
> > > get the occasionally fubarred value?
> > >
> > >From view of user-support saler, if terrible broken value is reported,
> > it will be user-incident and annoy me(us) ;)
> >
> > I'd like to get rid of rq->lock, too..Hmm.. some routine like
> > atomic64_read() can help this ? (But I don't want to use atomic_t here..)
>
> atomic64_read() will not help you on a 32-bit machine. Here is the
> sequence of events that will cause the aforementioned user incidents and
> consequent annoyance:
>
> o The value of the counter is (2^32)-1, or 0xffffffff.
>
> o CPU 0 reads the high-order 32 bits of the counter, getting zero.
>
> o CPU 1 increments the low-order 32 bits of the counter, resulting
> in zero, but notes that there is a carry out of this field.
>
> o CPU 0 reads the low-order 32 bits of the counter, getting zero.
>
> o CPU 1 increments the high-order 32 bits of the counter, so that
> the new value of the counter is 2^32, or 0x100000000.
>
> So CPU 0 gets a value that is -way- off.
>
> The usual trick is something like the following for counter read:
>
> 1. Read the high-order 32 bits of the counter.
>
> 2. Do a memory barrier, smp_mb().
>
> 3. Read the low-order 32 bits of the counter.
>
> 4. Do another memory barrier, again smp_mb().
>
> 5. Read the high-order 32 bits of the counter again.
>
> If it is the same as the value obtained in step 1 (or the previous
> execution of step 5), then we are done. (This works even in case
> of complete 64-bit overflow, though we should be very lucky to
> live that long!) Otherwise, go to step 2.
>
> But it is also necessary to modify the counter update:
>
> 1. Increment the low-order 32 bits of the counter. If no overflow
> occurred, we are done, otherwise, continue through this sequence
> of steps.
>
> 2. Do a memory barrier, smp_mb().
>
> 3. Increment the high-order 32 bits of the counter.
>
> How to detect overflow in step 1? Well, if we are incrementing, we can
> just test for the new value being zero. Otherwise, if we are adding
> a 32-bit number, if the new value of the low-order 32 bits of counter
> is less than the old value, overflow occurred (but make sure that the
> comparison is unsigned!).
>
> This all assumes that you are adding a 32-bit quantity to the counter.
> Adding 64-bit values is not much harder.
>
> Does this approach work for you?
>
Thank you. I'll try some and post if it seems easy to read/merge.
Hmm, but in your approach, can't we see the counter goes backword ?
(if the reader see only low 32 bit is incremtend.)
Can't we use seq_counter in include/linux/seqlock.h ?
There is only one writer and we don't need write-side lock.
Thanks,
-Kame
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