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Message-ID: <20090501174228.GB9565@elte.hu>
Date: Fri, 1 May 2009 19:42:28 +0200
From: Ingo Molnar <mingo@...e.hu>
To: Steven Rostedt <rostedt@...dmis.org>
Cc: linux-kernel@...r.kernel.org,
Andrew Morton <akpm@...ux-foundation.org>,
Frederic Weisbecker <fweisbec@...il.com>
Subject: Re: [PATCH 3/3] ring-buffer: make cpu buffer entries counter atomic
* Steven Rostedt <rostedt@...dmis.org> wrote:
>
> On Fri, 1 May 2009, Ingo Molnar wrote:
>
> >
> > * Steven Rostedt <rostedt@...dmis.org> wrote:
> >
> > > On Fri, 1 May 2009, Ingo Molnar wrote:
> > > > > The entries keeps track of the number of entries in the buffer. A
> > > > > writer (producer) adds to the counter and readers (consumers)
> > > > > subtract from them. A writer can subtract them if it overwrites a
> > > > > page before the producer consumes it.
> > > > >
> > > > > Only the writers are pinned to a CPU, the readers happen on any
> > > > > CPU.
> > > >
> > > > But that does not require atomicity. It requires careful use of
> > > > barriers, but otherwise atomicity is not needed. Update of machine
> > > > word variables (if they are aligned to a machine word) is guaranteed
> > > > to be atomic, even without atomic_t overhead.
> > >
> > > I'm confused :-/ This throws out all that I learned in multi threaded
> > > programming.
> > >
> > > If I have a shared variable used by two threads, the adding and
> > > subtracting of that variable does not need to be atomic?
> > >
> > > CPU0 CPU1
> > > ---- ----
> > > load A load A
> > > sub 1, A sub 1, A
> > > store A store A
> > >
> > > can work??
> >
> > no, that wont work. But as long as there's just a single CPU that is
> > a _writer_ (does stores), it can be observed in an atomic/coherent
> > manner, without the use of atomics.
>
> Ah, maybe there's confusion in my explanation. When I talk about
> writers and readers, I'm talking about those writers into the ring
> buffer and readers from the ring buffer. But both writers and
> readers write to the entries counter. Readers subtract and writers
> add. But writers can also subtract on overruns.
a solution for that would be to split it into two counts - for both
sides. Or to eliminate it if possible. We _really_ need to make the
ring-buffer _much_ cheaper than it is today.
y
Ingo
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