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Message-ID: <20090518164440.2124a4fa@hyperion.delvare>
Date: Mon, 18 May 2009 16:44:40 +0200
From: Jean Delvare <khali@...ux-fr.org>
To: Linus Walleij <linus.ml.walleij@...il.com>
Cc: Mike Rapoport <mike@...pulab.co.il>, linux-kernel@...r.kernel.org,
sameo@...ux.intel.com, linux-i2c@...r.kernel.org,
Linus Walleij <linus.walleij@...ricsson.com>
Subject: Re: [PATCH] MFD: Add U300 AB3100 core support v1
Hi Linus,
On Mon, 18 May 2009 16:22:36 +0200, Linus Walleij wrote:
> Here we have a problem. See above:
> msgs[0].addr = ab3100_i2c_client->addr + 1;
>
> So this chip actually has two addresses. A "special" address
> to deal with test registers, one address up. The I2C framework
> assume all devices have one and one address only (which is
> of course mostly true).
No, the I2C framework doesn't assume this. All the I2C framework
assumes is that only one device can use a given address on any one I2C
segment (which seems reasonable.)
> Here is a special case. When the first device has registered,
> you know that the other address is available as well.
>
> You could think of several ugly solutions:
>
> * Keep using i2c_transfer() directly as we do now.
>
> * Make a raw copy of the i2c_device with something like
> memcpy(mock_client, i2c_client, sizeof(i2c_client);
> mock_client->addr++;
> then use i2c_master_send()
>
> * Register a new i2c_device in board_info for the other
> address while strictly speaking it is the same device, and
> this will yield a lot of probing and synchronization code,
> because writing the test registers is used when probing the
> first device, so we have to wait for that device to be probed
> before we can probe the other one etc.
>
> Right now I lean toward the first alternative.
Neither is correct. Simply use i2c_new_dummy() on the second I2C
address, and keep a pointer to the instantiated i2c_client for future
use. Don't forget to call i2c_unregister_device() in your .remove()
method.
--
Jean Delvare
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