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Message-ID: <20091014182037.GA10076@redhat.com>
Date: Wed, 14 Oct 2009 20:20:37 +0200
From: Oleg Nesterov <oleg@...hat.com>
To: Linus Torvalds <torvalds@...ux-foundation.org>
Cc: Alan Cox <alan@...rguk.ukuu.org.uk>,
Paul Fulghum <paulkf@...rogate.com>,
Boyan <btanastasov@...oo.co.uk>,
"Rafael J. Wysocki" <rjw@...k.pl>,
Linux Kernel Mailing List <linux-kernel@...r.kernel.org>,
Kernel Testers List <kernel-testers@...r.kernel.org>,
Dmitry Torokhov <dmitry.torokhov@...il.com>,
Ed Tomlinson <edt@....ca>,
OGAWA Hirofumi <hirofumi@...l.parknet.co.jp>
Subject: Re: [Bug #14388] keyboard under X with 2.6.31
On 10/14, Linus Torvalds wrote:
>
> Of course, keventd itself is multi-threaded, so I'm not entirely sure even
> -that- guarantees that one 'flush_to_ldisc()' couldn't be pending on one
> CPU while it is then scheduled and then run on another CPU concurrently
> too. The WORK_STRUCT_PENDING bit guarantees exclusion from the lists and
> from being pending, but the work might be both pending and _running_ at
> the same time, afaik.
Yes.
> void tty_flush_to_ldisc(struct tty_struct *tty)
> {
> - flush_to_ldisc(&tty->buf.work.work);
> + flush_delayed_work(&tty->buf.work);
> }
Can't comment this change because I don't understand the problem.
> + * flush_delayed_work - block until a dwork_struct's callback has terminated
> + * @dwork: the delayed work which is to be flushed
> + *
> + * Any timeout is cancelled, and any pending work is run immediately.
> + */
> +void flush_delayed_work(struct delayed_work *dwork)
> +{
> + if (del_timer(&dwork->timer)) {
> + struct cpu_workqueue_struct *cwq;
> + cwq = wq_per_cpu(keventd_wq, get_cpu());
> + __queue_work(cwq, &dwork->work);
> + put_cpu();
> + }
> + flush_work(&dwork->work);
> +}
I think this is correct. If del_timer() succeeds, we "own" _PENDING bit and
dwork->work must not be queued. But afaics this helper needs del_timer_sync(),
otherwise I am not sure about the "flush" part.
Let's suppose this dwork was pending and del_timer() returns 0. Since we use
del_timer, not del_timer_sync, it is possible that delayed_work_timer_fn() is
running in parallel, and the queueing is in progress. In this case flush_work()
can just return, before delayed_work_timer_fn() actually queues this dwork.
And just in case... Of course, if dwork was pending and running on another CPU,
then flush_delayed_work(dwork) can return before the running callback terminates.
But I guess this is what we want.
As for tty_flush_to_ldisc(), what if tty->buf.work.work was not scheduled?
In this case flush_delayed_work() does nothing. Is it OK?
Oleg.
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