linux-kernel - Re: [PATCH] cfq-iosched: non-rot devices do not need read queue merging

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Message-ID: <20100104185100.GF7968@redhat.com>
Date:	Mon, 4 Jan 2010 13:51:00 -0500
From:	Vivek Goyal <vgoyal@...hat.com>
To:	Corrado Zoccolo <czoccolo@...il.com>
Cc:	Jeff Moyer <jmoyer@...hat.com>, Jens Axboe <jens.axboe@...cle.com>,
	Linux-Kernel <linux-kernel@...r.kernel.org>,
	Shaohua Li <shaohua.li@...el.com>,
	Gui Jianfeng <guijianfeng@...fujitsu.com>
Subject: Re: [PATCH] cfq-iosched: non-rot devices do not need read queue
	merging

On Mon, Jan 04, 2010 at 07:37:17PM +0100, Corrado Zoccolo wrote:
> On Mon, Jan 4, 2010 at 5:51 PM, Jeff Moyer <jmoyer@...hat.com> wrote:
> > Corrado Zoccolo <czoccolo@...il.com> writes:
> >
> >> Hi Vivkek,
> >>
> >> On Mon, Jan 4, 2010 at 3:47 PM, Vivek Goyal <vgoyal@...hat.com> wrote:
> >>> On Wed, Dec 30, 2009 at 11:22:47PM +0100, Corrado Zoccolo wrote:
> >>>> Non rotational devices' performances are not affected by
> >>>> distance of read requests, so there is no point in having
> >>>> overhead to merge such queues.
> >>>> This doesn't apply to writes, so this patch changes the
> >>>> queued[] field, to be indexed by READ/WRITE instead of
> >>>> SYNC/ASYNC, and only compute proximity for queues with
> >>>> WRITE requests.
> >>>>
> >>>
> >>> Hi Corrado,
> >>>
> >>> What's the reason that reads don't benefit from merging queues and hence
> >>> merging requests and only writes do on SSD?
> >>
> >> On SSDs, reads are just limited by the maximum transfer rate, and
> >> larger (i.e. merged) reads will just take proportionally longer.
> >
> > This is simply not true.  You can get more bandwidth from an SSD (I just
> > checked numbers for 2 vendors' devices) by issuing larger read requests,
> > no matter whether the access pattern is sequential or random.
> I know, but the performance increase given the size is sublinear, and
> the situation here is slightly different.
> In order for the requests to be merged, they have to be submitted concurrently.
> So you have to compare 2 concurrent requests of size x with one
> request of size 2*x (with some CPU overhead).
> Moreover, you always pay the CPU overhead, even if you can't do the
> merging, and you must be very lucky to keep merging, because it means
> the two processes are working in lockstep; it is not sufficient that
> the requests are just nearby, as for rotational disks.
> 

For jeff, at least "dump" utility threads were kind of working in lockstep
for writes and he gained significantly by merging these queues together.

So the argument is that CPU overhead saving in this case is more substantial
as compared to gains made by lockstep read threads. I think we shall have to
have some numbers to justify that.

Thanks
Vivek
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