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Message-ID: <20100413183537.GA17538@redhat.com>
Date: Tue, 13 Apr 2010 20:35:37 +0200
From: Oleg Nesterov <oleg@...hat.com>
To: Srikar Dronamraju <srikar@...ux.vnet.ibm.com>
Cc: Peter Zijlstra <peterz@...radead.org>, Ingo Molnar <mingo@...e.hu>,
Andrew Morton <akpm@...ux-foundation.org>,
Linus Torvalds <torvalds@...ux-foundation.org>,
Masami Hiramatsu <mhiramat@...hat.com>,
Randy Dunlap <rdunlap@...otime.net>,
Ananth N Mavinakayanahalli <ananth@...ibm.com>,
Jim Keniston <jkenisto@...ux.vnet.ibm.com>,
Frederic Weisbecker <fweisbec@...il.com>,
"Frank Ch. Eigler" <fche@...hat.com>,
LKML <linux-kernel@...r.kernel.org>,
Roland McGrath <roland@...hat.com>
Subject: Re: [PATCH v2 7/11] Uprobes Implementation
On 03/31, Srikar Dronamraju wrote:
>
> --- /dev/null
> +++ b/kernel/uprobes.c
> ...
> +static struct uprobe_process *find_uprocess(struct pid *tg_leader)
> +{
> + struct uprobe_process *uproc;
> + struct task_struct *tsk = get_pid_task(tg_leader, PIDTYPE_PID);
> +
> + if (!tsk)
> + return NULL;
> +
> + if (!tsk->utask || !tsk->utask->uproc) {
> + put_task_struct(tsk);
> + return NULL;
> + }
> +
> + uproc = tsk->utask->uproc;
> + BUG_ON(uproc->tg_leader != tg_leader);
> + atomic_inc(&uproc->refcount);
> + put_task_struct(tsk);
> + return uproc;
Looks like, this doesn't need get/put task_struct, you could just
use pid_task() under rcu_read_lock().
> +static void cleanup_uprocess(struct uprobe_process *uproc,
> + struct task_struct *start)
> +{
> + struct task_struct *tsk = start;
> +
> + if (!start)
> + return;
> +
> + rcu_read_lock();
> + do {
> + if (tsk->utask) {
> + kfree(tsk->utask);
> + tsk->utask = NULL;
> + }
> + tsk = next_thread(tsk);
This doesn't look right. We can't trust ->thread_group list even under
rcu_read_lock(). The task can exit and __exit_signal() can remove it
from ->thread_group list before we take rcu_read_lock().
> +static struct uprobe_task *add_utask(struct task_struct *t,
> + struct uprobe_process *uproc)
> +{
> + struct uprobe_task *utask;
> +
> + if (!t)
> + return NULL;
> + utask = kzalloc(sizeof *utask, GFP_USER);
> + if (unlikely(utask == NULL))
> + return ERR_PTR(-ENOMEM);
> +
> + utask->uproc = uproc;
> + utask->active_ppt = NULL;
> + t->utask = utask;
> + atomic_inc(&uproc->refcount);
> +
> + return utask;
> +}
This is called by create_uprocess(). Who will free t->utask if t has
already passed tracehook_report_exit() ?
> +static struct task_struct *find_next_thread(struct uprobe_process *uproc,
> + struct task_struct *start)
> +{
> + struct task_struct *next_t = NULL;
> +
> + rcu_read_lock();
> + if (start) {
> + struct task_struct *t = start;
> +
> + do {
> + if (unlikely(t->flags & PF_EXITING))
> + goto dont_add;
not sure I understand this check. Somehow we should prevent the races
with tracehook_report_exit/tracehook_report_exec, but PF_EXITING can't
help ?
> +dont_add:
> + t = next_thread(t);
> + } while (t != start);
again, this doesn't look right. Btw, I'd suggest to use while_each_thread().
> +static struct uprobe_process *create_uprocess(struct pid *tg_leader)
> +{
> ...
> + /*
> + * Create and populate one utask per thread in this process. We
> + * can't call add_utask() while holding RCU lock, so we:
> + * 1. rcu_read_lock()
> + * 2. Find the next thread, add_me, in this process that's not
> + * having a utask struct allocated.
> + * 3. rcu_read_unlock()
> + * 4. add_utask(add_me, uproc)
> + * Repeat 1-4 'til we have utasks for all threads.
> + */
> + cur_t = get_pid_task(tg_leader, PIDTYPE_PID);
> + do {
> + utask = add_utask(cur_t, uproc);
> + if (IS_ERR(utask)) {
> + err = PTR_ERR(utask);
> + goto fail;
> + }
> + add_me = find_next_thread(uproc, cur_t);
> + put_task_struct(cur_t);
> + cur_t = add_me;
> + } while (add_me != NULL);
can't we race with clone(CLONE_THREAD) and miss the new thread? Probably
I missed something, but afaics we need some barriers to ensure that either
tracehook_report_clone() sees current->utask != NULL or find_next_thread()
sees the new thread in ->thread_group.
> +static struct pid *get_tg_leader(pid_t p)
> +{
> + struct pid *pid = NULL;
> +
> + rcu_read_lock();
> + if (current->nsproxy)
> + pid = find_vpid(p);
Is it really possible to call register/unregister with nsproxy == NULL?
> + if (pid) {
> + struct task_struct *t = pid_task(pid, PIDTYPE_PID);
> +
> + if (!t || unlikely(t->flags & PF_EXITING))
Why do we check PF_EXITING?
> +int register_uprobe(struct uprobe *u)
> +{
> + struct uprobe_process *uproc;
> + struct uprobe_probept *ppt;
> + struct pid *p;
> + int ret = 0;
> +
> + if (!u || !u->handler)
> + return -EINVAL;
> +
> + p = get_tg_leader(u->pid);
> + if (!p)
> + return -ESRCH;
> +
> +
> + /* Get the uprobe_process for this pid, or make a new one. */
> + mutex_lock(&uprobe_mutex);
> + uproc = find_uprocess(p);
> +
> + if (!uproc) {
> + uproc = create_uprocess(p);
> + if (IS_ERR(uproc)) {
> + ret = (int) PTR_ERR(uproc);
> + mutex_unlock(&uprobe_mutex);
> + goto fail_tsk;
> + }
> + }
> + mutex_unlock(&uprobe_mutex);
> + mutex_lock(&uproc->mutex);
> +
> + if (uproc->n_ppts >= MAX_USER_BKPT_XOL_SLOTS)
> + goto fail_uproc;
> +
> + ret = xol_validate_vaddr(p, u->vaddr, uproc->xol_area);
OK, uproc and p can't go away. But why it is safe to use pid_task(p) ?
I am looking at 6th patch http://marc.info/?l=linux-kernel&m=127005086102256
and xol_validate_vaddr() calls pid_task() without rcu and doesn't check
the result is not NULL.
We already dropped uprobe_mutex, can't this task exit?
> +void uprobe_handle_clone(unsigned long clone_flags,
> + struct task_struct *child)
> +{
> + struct uprobe_process *uproc;
> + struct uprobe_task *ptask, *ctask;
> +
> + ptask = current->utask;
> + if (!ptask)
> + return;
> +
> + uproc = ptask->uproc;
> +
> + if (clone_flags & CLONE_THREAD) {
> + mutex_lock(&uprobe_mutex);
> + /* New thread in the same process. */
> + ctask = child->utask;
> + if (unlikely(ctask)) {
> + /*
> + * create_uprocess() ran just as this clone
> + * happened, and has already accounted for the
> + * new child.
> + */
> + } else
> + ctask = add_utask(child, uproc);
This looks a bit strange. Why do we need "ctask" at all? It is not used,
you could just do
if (likely(!child->utask))
add_utask(child, uproc);
The same for "else" branch.
> + } else {
> + struct uprobe_probept *ppt;
> + int ret;
> +
> + /*
> + * New process spawned by parent. Remove the probepoints
> + * in the child's text.
> + *
> + * We also hold the uproc->mutex for the parent - so no
> + * new uprobes will be registered 'til we return.
> + */
> + mutex_lock(&uproc->mutex);
> + ctask = child->utask;
> + if (unlikely(ctask)) {
> + /*
> + * create_uprocess() ran just as this fork
> + * happened, and has already created a new utask.
> + */
> + mutex_unlock(&uproc->mutex);
> + return;
> + }
> + list_for_each_entry(ppt, &uproc->uprobe_list, ut_node) {
> + ret = user_bkpt_remove_bkpt(child, &ppt->user_bkpt);
OK, iiuc this should restore the original instruction, right?
But what about clone(CLONE_VM)? In this case this child shares ->mm with
parent.
Oleg.
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