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Message-ID: <15749.1276551633@localhost>
Date:	Mon, 14 Jun 2010 17:40:33 -0400
From:	Valdis.Kletnieks@...edu
To:	Chase Douglas <chase.douglas@...onical.com>
Cc:	Steven Rostedt <srostedt@...hat.com>, linux-kernel@...r.kernel.org
Subject: Re: [PATCH] trace-cmd: prevent print_graph_duration buffer overflow

On Sun, 13 Jun 2010 17:01:34 EDT, Chase Douglas said:
> On Sun, 2010-06-13 at 16:52 -0400, Valdis.Kletnieks@...edu wrote:
> > On Sun, 13 Jun 2010 13:11:48 EDT, Chase Douglas said:
> > > Passing n > sizeof(string) to snprintf can cause a glibc buffer overflow
> > > condition. We know the exact size of nsecs_str, so use it instead of
> > > math that may overflow.
> > 
> > >  	/* Print nsecs (we don't want to exceed 7 numbers) */
> > >  	if ((s->len - len) < 7) {
> > > -		snprintf(nsecs_str, 8 - (s->len - len), "%03lu", nsecs_rem);
> > > +		snprintf(nsecs_str, sizeof(nsecs_str), "%03lu", nsecs_rem);
> > 
> > We only get into this code after we've checked that the length is under 7
> > characters.  How much overflow can happen as long as the sizeof(nsecs_str) is a
> > sane size (like at least 8 chars)?  Probably a better bet would be doing the
> > right thing and 'BUILD_BUG_ON(sizeof(nsecs_str) < 8);'?
> 
> nsecs_str is a local variable defined just above this block of code as:
> 
> 	char nsecs_str[5];
> 
> I was hitting cases where s->len == 64 and len == 63, leading to the
> size argument of snprintf being 7 on a 5 byte string. I didn't delve too
> much into the reasoning for the if statement, but I think it's math is
> not actually related to the size of nsecs_rem but to some other string
> length.

This is starting to smell like that patch is just papering over a bug...

I saw that '8 -' and made the rash assumption that was the size of the array.
Is 5 in fact big enough and the  's->len - len' calculation is broken, or
should it be bigger?  As you noted, that length calculation is looking a tad
sketchy.  (And if we're stuck with '5' because it's a magic number for
somebody's formatting purposes, maybe it needs to be a #define?)


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