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Message-ID: <20100929141945.5e28f560@schatten.dmk.lab>
Date: Wed, 29 Sep 2010 14:19:45 +0200
From: Florian Mickler <florian@...kler.org>
To: Florian Mickler <florian@...kler.org>
Cc: tmhikaru@...il.com, linux-kernel@...r.kernel.org,
Greg KH <gregkh@...e.de>
Subject: Re: Linux 2.6.35.6
On Wed, 29 Sep 2010 13:52:48 +0200
Florian Mickler <florian@...kler.org> wrote:
> On Wed, 29 Sep 2010 07:02:48 -0400
> tmhikaru@...il.com wrote:
> > > Yes, the sample rate was one of the things I wanted to know, but also which of
> > > the 3 load figures you were graphing.
> > To be honest, I actually don't know. I'm *terrible* at regex, this is what
> > the bash script is doing:
>
> It's taking the first column of the line in /proc/loadavg which
> corresponds to the 15 min avg on my machine.
Actually, no. It's the 1 min avg...
Try using
awk '{print $3}' /proc/loadavg
but I don't think it necesserily invalidates your bisection results.
Regards,
Flo
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