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Message-ID: <AANLkTi=_siOR8QtXdW07ZY1mFG9_A2806erd64cRNRCb@mail.gmail.com>
Date: Mon, 25 Oct 2010 14:43:35 -0700
From: Linus Torvalds <torvalds@...ux-foundation.org>
To: David Howells <dhowells@...hat.com>
Cc: akpm@...ux-foundation.org, Tejun Heo <tj@...nel.org>,
linux-am33-list@...hat.com, linux-kernel@...r.kernel.org,
Akira Takeuchi <takeuchi.akr@...panasonic.com>,
Mark Salter <msalter@...hat.com>
Subject: Re: [PATCH] workqueue: Fix alignment calculation in alloc_cwqs()
On Mon, Oct 25, 2010 at 2:27 PM, David Howells <dhowells@...hat.com> wrote:
> In the MN10300 arch, we occasionally see an assertion being tripped in
> alloc_cwqs() at the following line:
>
> /* just in case, make sure it's actually aligned */
> ---> BUG_ON(!IS_ALIGNED(wq->cpu_wq.v, align));
> return wq->cpu_wq.v ? 0 : -ENOMEM;
>
> The values are:
>
> wa->cpu_wq.v => 0x902776e0
> align => 0x100
>
> and align is calculated by the following:
>
> const size_t align = max_t(size_t, 1 << WORK_STRUCT_FLAG_BITS,
> __alignof__(unsigned long long));
>
> which is wrong. __alignof__() returns its value in bytes, but:
>
> 1 << WORK_STRUCT_FLAG_BITS
>
> returns the value in bits. It needs dividing by the number of bits in a byte.
No it doesn't. Those bits really require that many bytes of alignment.
Think about it: if the low 8 bits of the pointer are used for flags,
then the actual pointer itself needs to be aligned to a 256-byte
boundary.
So the code is right. If needs to ask for "1 << WORK_STRUCT_FLAG_BITS"
alignment, and if it doesn't get it (because the allocator is somehow
broken - percpu allocator issues?), things will break.
Linus
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