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Message-ID: <20101128202535.GC12896@redhat.com>
Date: Sun, 28 Nov 2010 21:25:35 +0100
From: Oleg Nesterov <oleg@...hat.com>
To: Tejun Heo <tj@...nel.org>
Cc: roland@...hat.com, linux-kernel@...r.kernel.org,
torvalds@...ux-foundation.org, akpm@...ux-foundation.org,
"rjw@...k.plpavel"@ucw.cz,
Jan Kratochvil <jan.kratochvil@...hat.com>
Subject: Re: [PATCH 09/14] ptrace: clean transitions between TASK_STOPPED
and TRACED
On 11/26, Tejun Heo wrote:
>
> Currently, if the task is STOPPED on ptrace attach, it's left alone
> and the state is silently changed to TRACED on the next ptrace call.
> The behavior breaks the assumption that arch_ptrace_stop() is called
> before any task is poked by ptrace operations and is ugly in that a
> task manipulates the state of another task directly.
>
> With GROUP_STOP_PENDING, the transitions between TASK_STOPPED and
> TRACED can be made clean. The tracer can use the flag to tell the
> tracee to retry stop on attach and detach. On retry, the tracee will
> enter the desired state the correct way. The lower 16bits of
> task->group_stop is used to remember the signal number which caused
> the last group stop. This is used while retrying for ptrace attach as
> the original group_exit_code could have been consumed with wait(2) by
> then.
This adds another user-visible change, this time it is more serious.
Again, I do not claim it breaks ptrace, just I do not know.
> @@ -204,6 +202,19 @@ int ptrace_attach(struct task_struct *task)
> __ptrace_link(task, current);
> send_sig_info(SIGSTOP, SEND_SIG_FORCED, task);
>
> + /*
> + * If the task is already STOPPED, set GROUP_STOP_PENDING and
> + * kick it so that it transits to TRACED. This is safe as
> + * both transitions in and out of STOPPED are protected by
> + * siglock.
> + */
> + spin_lock(&task->sighand->siglock);
> + if (task_is_stopped(task)) {
> + task->group_stop |= GROUP_STOP_PENDING;
> + signal_wake_up(task, 1);
OK. Now we have a window if the tracer attaches to the stopped task.
Say,
child = fork()
if (!child)
return child_do_something();
kill(child, SIGSTOP);
wait(); // <--- ensures it is stopped
ptrace(PTRACE_ATTACH, child);
assert(ptrace(PTRACE_WHATEVER, child) == 0);
Currently this code is correct. With this patch the assertion above
can fail, the child may be running, changing its state from STOPPED
to TRACED.
> @@ -1793,7 +1797,7 @@ static int do_signal_stop(int signr)
>
> if (consume_group_stop())
> sig->flags = SIGNAL_STOP_STOPPED;
> -
> +retry:
> current->exit_code = sig->group_exit_code;
> current->group_stop &= ~GROUP_STOP_PENDING;
> __set_current_state(TASK_STOPPED);
> @@ -1805,6 +1809,7 @@ static int do_signal_stop(int signr)
> read_lock(&tasklist_lock);
> do_notify_parent_cldstop(current, notify);
> read_unlock(&tasklist_lock);
> + notify = 0;
> }
>
> /* Now we don't run again until woken by SIGCONT or SIGKILL */
> @@ -1812,7 +1817,13 @@ static int do_signal_stop(int signr)
>
> spin_lock_irq(¤t->sighand->siglock);
> } else
> - ptrace_stop(current->exit_code, CLD_STOPPED, 0, NULL);
> + ptrace_stop(current->group_stop & GROUP_STOP_SIGMASK,
> + CLD_STOPPED, 0, NULL);
> +
> + if (current->group_stop & GROUP_STOP_PENDING) {
> + WARN_ON_ONCE(!(current->group_stop & GROUP_STOP_SIGMASK));
> + goto retry;
This doesn't look right even without ptrace.
Suppose we have to threads, T1 and T2, both stopped, SIGNAL_STOP_STOPPED
is set.
SIGCONT wakes them up.
To simplify the discussion, suppose that T1 takes a long preemption
when it returns from schedule(), right before it takes ->siglock again.
T2 sends CLD_CONTINUED to parent and dequeues another SIGSTOP. It
initiates another group stop, sees T1 as running, and stops with
->group_stop_count == 1. Now we are waiting for T1 which should
participate.
Finally T1 resumes and sees GROUP_STOP_PENDING. It goes to 'retry:'
and stops, but nobody notifies the parent ang ->group_stop_count is
still non-zero.
Oleg.
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