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Message-ID: <AANLkTineieNdiKduDHQ-J+Xv6Pq9O0pTZraBJEw=p5e7@mail.gmail.com>
Date: Wed, 19 Jan 2011 12:35:45 +0800
From: Yong Zhang <yong.zhang0@...il.com>
To: Mike Galbraith <efault@....de>
Cc: Peter Zijlstra <peterz@...radead.org>, samu.p.onkalo@...ia.com,
mingo@...e.hu,
"linux-kernel@...r.kernel.org" <linux-kernel@...r.kernel.org>,
tglx <tglx@...utronix.de>
Subject: Re: Bug in scheduler when using rt_mutex
On Wed, Jan 19, 2011 at 11:43 AM, Mike Galbraith <efault@....de> wrote:
>> (cfs_rq->curr != se) equals to (!running), no?
>
> No, running is task_of(se) == rq->curr. Another class or fair group
> task may be rq_of(cfs_rq)->curr
If task_of(se) != rq->curr, as you said it maybe on another class or
fair group; then for its fair group, cfs_rq->curr == NULL.
cfs_rq->curr != se is always true.
Thanks,
Yong
--
Only stand for myself
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