linux-kernel - Re: [PATCH 1/4] userns: let clone_uts_ns() handle setting uts->user

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Date:	Mon, 21 Feb 2011 15:23:30 +0100
From:	Daniel Lezcano <daniel.lezcano@...e.fr>
To:	"Serge E. Hallyn" <serge@...lyn.com>
CC:	Oleg Nesterov <oleg@...hat.com>, Andrew Morton <akpm@...l.org>,
	LSM <linux-security-module@...r.kernel.org>,
	James Morris <jmorris@...ei.org>,
	Kees Cook <kees.cook@...onical.com>,
	containers@...ts.linux-foundation.org,
	kernel list <linux-kernel@...r.kernel.org>,
	"Eric W. Biederman" <ebiederm@...ssion.com>,
	Alexey Dobriyan <adobriyan@...il.com>,
	Michael Kerrisk <mtk.manpages@...il.com>, xemul@...allels.com,
	dhowells@...hat.com
Subject: Re: [PATCH 1/4] userns: let clone_uts_ns() handle setting uts->user_ns

On 02/21/2011 02:58 PM, Serge E. Hallyn wrote:
> Quoting Oleg Nesterov (oleg@...hat.com):
>> On 02/21, Daniel Lezcano wrote:
>>> On 02/21/2011 05:01 AM, Serge E. Hallyn wrote:
>>>> To do so we need to pass in the task_struct who'll get the utsname,
>>>> so we can get its user_ns.
>>>>
>>>> -extern struct uts_namespace *copy_utsname(unsigned long flags,
>>>> -					struct uts_namespace *ns);
>>>> +extern struct uts_namespace *copy_utsname(struct task_struct *tsk,
>>>> +					  unsigned long flags,
>>>> +					  struct uts_namespace *ns);
>>> Why don't we pass 'user_ns' instead of 'tsk' ? that will look
>>> semantically clearer for the caller no ?
>>> (example below).
>>> ...
>>>
>>> new_nsp->uts_ns = copy_utsname(flags, tsk->nsproxy->uts_ns, task_cred_xxx(tsk, user)->user_ns);
>> To me tsk looks more readable, I mean
>>
>> 	new_nsp->uts_ns = copy_utsname(flags, tsk);
>>
>> copy_utsname() can find both uts_ns and user_ns looking at task_strcut.
> Uh, yeah.  I should remove the 'ns' argument there shouldn't I.
>
> Daniel, does that sway your opinion then?

Well, I prefer to pass the needed parameters to a function. AFAICS, 
'tsk' is not really needed but 'user_ns'.
But it is a detail, so if passing the tsk parameter in the other copy_* 
functions helps to cleanup, that will be consistent.
So I am fine with that.

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