linux-kernel - Re: [PATCH 5/7] seccomp_filter: Document what seccomp

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Message-ID: <1304511396.25414.2422.camel@gandalf.stny.rr.com>
Date:	Wed, 04 May 2011 08:16:36 -0400
From:	Steven Rostedt <rostedt@...dmis.org>
To:	Frederic Weisbecker <fweisbec@...il.com>
Cc:	Will Drewry <wad@...omium.org>, Eric Paris <eparis@...hat.com>,
	Ingo Molnar <mingo@...e.hu>, linux-kernel@...r.kernel.org,
	kees.cook@...onical.com, agl@...omium.org, jmorris@...ei.org,
	Randy Dunlap <rdunlap@...otime.net>,
	Linus Torvalds <torvalds@...ux-foundation.org>,
	Andrew Morton <akpm@...ux-foundation.org>,
	Tom Zanussi <tzanussi@...il.com>,
	Arnaldo Carvalho de Melo <acme@...hat.com>,
	Peter Zijlstra <a.p.zijlstra@...llo.nl>,
	Thomas Gleixner <tglx@...utronix.de>
Subject: Re: [PATCH 5/7] seccomp_filter: Document what seccomp_filter is
 and how it works.

On Tue, 2011-05-03 at 03:47 +0200, Frederic Weisbecker wrote:
> 2011/5/3 Frederic Weisbecker <fweisbec@...il.com>:

> Even better: applying a filter would always automatically be an
> intersection of the previous one.
> 
> If you do:
> 
> SECCOMP_FILTER_SET, __NR_foo, "a == 1 || a == 2"
> SECCOMP_FILTER_APPLY
> SECCOMP_FILTER_SET, __NR_foo, "b == 2"
> SECCOMP_FILTER_APPLY
> SECCOMP_FILTER_SET, __NR_foo, "c == 3"
> SECCOMP_FILTER_APPLY
> 
> The end result is:
> 
> "(a == 1 || a == 2) && b == 2  && c == 3"
> 

I'm a little confused. Why do we have both a FILTER_SET and a
FILTER_APPLY? Maybe this was discussed earlier in the thread and I
missed it or simply forgot.

Why not just apply on the set call?

-- Steve


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