linux-kernel - Re: ramoops: is using platform

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Message-ID: <BANLkTi=UeEEj0fRb9v1viFpUOWvmrSHM2g@mail.gmail.com>
Date:	Tue, 24 May 2011 13:49:34 +0800
From:	Américo Wang <xiyou.wangcong@...il.com>
To:	Kyungmin Park <kmpark@...radead.org>
Cc:	Stevie Trujillo <stevie.trujillo@...il.com>,
	marco.stornelli@...il.com, linux-kernel@...r.kernel.org
Subject: Re: ramoops: is using platform_drivers correct?

On Tue, May 24, 2011 at 1:32 PM, Kyungmin Park <kmpark@...radead.org> wrote:
> On Mon, May 23, 2011 at 11:36 PM, Kyungmin Park <kmpark@...radead.org> wrote:
>> Hi,
>>
>> You have to define the ramoops platform data at your board file and
>> pass it to the platform device init.
>> As these address is different for each SoCs. e.g., x86, and Samsung
>> ARM SoCs and so on.
>>
>> I think maybe you use the x86 so define the default x86 ram address
>> for ramoops and pass it to platform structures.

Why not document this?

>>
>> At office, I will send the sample usage.
>
> +static struct ramoops_platform_data goni_ramoops_data = {
> +       .mem_size               = SZ_16K,
> +       .mem_address            = 0xED000000,   /* SRAM */
> +};
> +
> +static struct platform_device goni_ramoops = {
> +       .name = "ramoops",
> +       .dev = {
> +               .platform_data = &goni_ramoops_data,
> +       },
> +};
>
> and register the goni_rammoops. then you can find a rammops.
>

Huh? Is this for x86 too? Why so unfriendly for end-users?

I think we need some kernel parameter like 'crashkernel=' (or memmap=)
to reserve memory for ramoops, right?

Thanks.
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