linux-kernel - Re: [PATCH] Introduce ActivePid: in /proc/self/status (v2, was Vpid:)

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Message-ID: <20110616123554.GA7230@hawkmoon.kerlabs.com>
Date:	Thu, 16 Jun 2011 14:35:55 +0200
From:	Louis Rilling <Louis.Rilling@...labs.com>
To:	Greg Kurz <gkurz@...ibm.com>
Cc:	Oleg Nesterov <oleg@...hat.com>, linux-kernel@...r.kernel.org,
	ebiederm@...ssion.com, containers@...ts.osdl.org,
	akpm@...ux-foundation.org, xemul@...nvz.org
Subject: Re: [PATCH] Introduce ActivePid: in /proc/self/status (v2, was
	Vpid:)

On 16/06/11 13:01 +0200, Greg Kurz wrote:
> On Wed, 2011-06-15 at 20:46 +0200, Oleg Nesterov wrote:
> > On 06/15, Greg Kurz wrote:
> > >
> > > @@ -176,6 +177,17 @@ static inline void task_state(struct seq_file *m, struct pid_namespace *ns,
> > >  		if (tracer)
> > >  			tpid = task_pid_nr_ns(tracer, ns);
> > >  	}
> > > +	actpid = 0;
> > > +	sighand = rcu_dereference(p->sighand);
> > > +	if (sighand) {
> > > +		struct pid_namespace *pid_ns;
> > > +		unsigned long flags;
> > > +		spin_lock_irqsave(&sighand->siglock, flags);
> > 
> > Well. This is not exactly right. We have lock_task_sighand() for this.
> > 
> 
> I see... ->sighand could change so we need the for(;;) loop in
> __lock_task_sighand() to be sure we have the right pointer, correct ?
> By the way, if we use lock_task_sighand() we'll end up with nested
> rcu_read_lock(): it will work but I don't know how it may affect
> performance...

rcu_read_lock() is very cheap.

> 
> > But. Why do you need ->siglock? Why rcu_read_lock() is not enough?
> > 
> 
> Because there's a race with
> __exit_signal()->__unhash_process()->detach_pid() that can break
> task_active_pid_ns() and rcu won't help here (unless *perhaps* by
> modifying __exit_signal() but I don't want to mess with such a critical
> path).

In case of race, the only risk is that task_active_pid_ns() returns NULL.
Otherwise, RCU guarantees that the pid_ns will stay alive (see below).

> 
> > Hmm. You don't even need pid_ns afaics, you could simply look at
> > pid->numbers[pid->level].
> > 
> 
> True but I will have the same problem: detach_pid() nullifies the pid.

But the pid won't be freed until an RCU grace period expires. See free_pid(). So
the non-determinism here is when /proc/<pid>/status is read at the same as
threaded execve() or task's exit(), in which case a stale pid (execve()) or
no pid (exit after __unhash_process()) can be accessed. This does not look like
a big deal...

Thanks,

Louis

> 
> Thanks for your comments.
> 
> --
> Greg
> 
> _______________________________________________
> Containers mailing list
> Containers@...ts.linux-foundation.org
> https://lists.linux-foundation.org/mailman/listinfo/containers

-- 
Dr Louis Rilling			Kerlabs
Skype: louis.rilling			Batiment Germanium
Phone: (+33|0) 6 80 89 08 23		80 avenue des Buttes de Coesmes
http://www.kerlabs.com/			35700 Rennes

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