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Message-ID: <BANLkTinacDgzZenwmG4==1gYfEaQg-YQ-g@mail.gmail.com>
Date: Tue, 28 Jun 2011 10:40:54 +0800
From: Yong Zhang <yong.zhang0@...il.com>
To: Cheng Xu <chengxu@...ux.vnet.ibm.com>
Cc: linux-kernel <linux-kernel@...r.kernel.org>,
Peter Zijlstra <peterz@...radead.org>,
Ingo Molnar <mingo@...e.hu>, Mike Galbraith <efault@....de>
Subject: Re: [PATCH] sched: skip autogroup when looking for all rt sched groups
Sorry for my late response and comments below.
On Thu, Jun 23, 2011 at 7:21 PM, Cheng Xu <chengxu@...ux.vnet.ibm.com> wrote:
>
> This looks like it works, but seems we might be able to do that with less code...
>
> static inline struct task_group *next_task_group(struct task_group *tg)
> {
> do {
> tg = list_entry_rcu(tg->list.next,
> typeof(struct task_group), list);
> } while ((&tg->list != &task_groups) && (task_group_is_autogroup(tg)));
> if (&tg->list == &task_groups)
> tg = NULL;
> return tg;
> }
>
> #define for_each_rt_rq(rt_rq, iter, rq) \
> for (iter = container_of(&task_groups, typeof(*iter), list); \
> (iter = next_task_group(iter)) && \
> (rt_rq = iter->rt_rq[cpu_of(rq)]);)
Yeah, this works too, and it save some code.
Will update the patch based on it.
Thanks,
Yong
--
Only stand for myself
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